$\bf (1-i)^3\implies ~\hfill \begin{array}{cccccccl} 1^3&+&3(1)^2(-i)^1&+&3(1)^1(i)^2&+&(-i)^3\\\\ 1&+&(-3i)&+&(3i^2)&+&(-i^3)\\\\ 1&-&3i&+&3i^2&-&i^3 \end{array} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{let's recall that}}{i^2=-1\qquad \qquad i^3=-i} \\\\[-0.35em] ~\dotfill\\\\ 1-3i+3(-1)-(-i)\implies 1-3i-3+i\implies -2-2i$

6 0

3 years ago

Show work and Evaluate 3/4 + 2/5

frez [133]

Answer:

23/20

Step-by-step explanation:

Find the common denominator of the 2 fractions (It's 20):

3/4 + 2/5

Multiply both numerator and denominator by 5 for the first fraction and multiply by 4 for the second fraction:

15/20 + 8/20

Add the fractions together:

23/20

5 0

2 years ago

Find the value of x^2+1/x^2 when <br>x-1/x=3

BaLLatris [955]

Answer:

sorry i couldnt help

Step-by-step explanation:

4 0

3 years ago