<em>IMPORTANT THIGNS TO REMEMBER:</em>
- Has 20 lb. dog food!
- Gives dog 1 3/5 everyday!
- Find how much eaten after 2 days!
- Find how much is left!
<em>ANSWER:</em>
Dog has eaten 3 1/5 after 2 days!
There is 16 4/5 left in bag!
<em>EXPLANATION:</em>
Since she gives 1 3/5 to her dog everyday and their asking for 2 days you would multiply 1 3/5 × 2 OR add 1 3/5 + 1 3/5
Which would give you 3 1/5
So, the dog has eaten 3 1/5 lb. of dog food in 2 days.
However then, you would subtract 20 lb. - 3 1/5 lb. because there is 20 lb. dog food in all and the dog has eaten 3 1/5 of it. This would give you 16 4/5 lb.
Meaning there is 16 4/5 lb. left in the bag of dog food!
Answer:
3 planes parallel to FL is EK, CI , BH, AJ
Because, this is prism in which all length segments should be equal .
A * b = 30
a - b = 1
a + b = 11
take ur last 2 equations, and add them
a - b = 1
a + b = 11
--------------add
2a = 12
a = 12/2
a = 6
now its just a matter of subbing
a + b = 11
6 + b = 11
b = 11 - 6
b = 5
so a = 6 and b = 5...whose product is 30, whose difference is 1, and whose sum is 11.
Answer/Step-by-step explanation:
✔️Find EC using Cosine Rule:
EC² = DC² + DE² - 2*DC*DE*cos(D)
EC² = 27² + 14² - 2*27*14*cos(32)
EC² = 925 - 756*cos(32)
EC² = 283.875639
EC = √283.875639
EC = 16.85 cm
✔️Find the area of ∆DCE:
Area = ½*14*27*sin(32)
Area of ∆DCE = 100.15 cm²
✔️Since ∆DCE and ∆ABE are congruent, therefore,
Area of ∆ABE = 100.15 cm²
✔️Find the area of the sector:
Area of sector = 105/360*π*16.85²
Area = 260.16 cm² (nearest tenth)
✔️Therefore,
Area of the logo = 100.15 + 100.15 + 260.16 = 460.46 ≈ 460 cm² (to 2 S.F)
Answer:
1. ΔXYZ is a right Δ with altitude YU.
Given
2. ΔXYZ ~ ΔYUZ
Right Triangle Altitude Similarity Theorem
3. VW || XY
Given
4. ∠VWZ ≅ ∠XYZ
Corresponding angles
5. ∠Z ≅ ∠Z
Reflexive property of congruence
6. ΔXYZ ~ ΔVWZ
AA Similarity postulate
7. ΔYUZ ~ ΔVWZ
Transitive property of similar triangles
Step-by-step explanation:
The first statement is given in the problem. Since we know the altitude of a right triangle, we can use the Right Triangle Altitude Similarity Theorem to say that the triangles formed by the altitude are similar to each other and the original triangle.
Next, we are given in the problem statement that the lines VW and XY are parallel. Therefore, ∠VWZ and ∠XYZ are corresponding angles, which makes them congruent. And since ∠Z is equal to itself (by reflexive property), we can use AA similarity to say ΔXYZ and ΔVWZ are similar.
Finally, combining statements 2 and 6, we can use transitive property to say that ΔYUZ and ΔVWZ are similar.
