Hello,
3(2x-5)+2(4-x)
=6x-15+8-2x
=4x-7
Steps to solve:
(-5q^2 + 6q + 7) - (-q^2 + 4q)
~Distribute the left side
-5q^2 + 6q + 7 + q^2 - 4q
~Combine like terms
-4q^2 + 2q + 7
Best of Luck!
The student is incorrect because if they were to reflect point A over the X-axis, this would mean they are moving it from its current quadrant to the one below. In that quadrant, the Y coordinate will be negative. So it couldn't possibly (6,3), because the 3 isn't negative.
Answer:
12
Step-by-step explanation:
Hope this helps!
