Answer:
4a-8
Step-by-step explanation:
(-4×a)+(-4×2)
Distributive property
For this case we define the following variables:
x: Number of party dresses
y: Number of suits
You have 30 hours per week to cut, that is, the first equation is given by:
It is also known that 25 hours per week are available for sewing, that is:
It has a system of two equations with two unknowns, solving we have:
Multiplying the second equation by -1:
Adding up:
Substituting x in the first equation:
Clearing and:
Thus, per week, the designer can produce 5 party dresses and 5 suits working at her maximum capacity.
Answer:
5 Party dresses
5 Suits
The percentage of the pins that will be acceptable to the customer is 63.16%.
<h3>What will the percentage be?</h3>
Based on the information, the probabilty that the pin lies is between 24.5 and 25.5. This will be illustrated as P(24.5 <x < 25.5).
So convert this into Z score, will be:
P(24.5 <x < 25.5):
= P((24.5-25.3)/0.45 <Z < (25.5-25.3)/0.45)
Solving this, we will get
P(-16/9<Z < 4/9) = P(-1.77 <Z < 0.44),
By looking at the z table and solving for Z by using P (Z<0.44)-P(Z>-1.77) will be:
= 0.67 -(1-0.9616)
= 0.6316
= 63.16%
Learn more about probability on:
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<u>Complete question</u>
A company supplies pins to a customer. It uses an automatic lathe to produce the pins. Due to factors such as vibration, temperature and wear and tear, the lengths of the pins and normally distributed with a mean of 25.30 mm and a standard deviation of 0.45 mm. The customer will only buy pins with lengths in the interval 25.00 ± 0.50 mm. What percentage of the pins will be acceptable to the customer?
Answer:
Step-by-step explanation:
5x 2 - 2x
Answer:
x=-11
Step-by-step explanation: