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3 years ago

Find the values of k such that the equation kx^2-x-1 = 0 has no real roots

Mathematics

1 answer:

stich3 [128]3 years ago

3 0

Kx^2-x-1=0
Kx^2-x=1
Kx^2=1+x
K=1+x/x^2

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If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

<em>Hence, the second term is 200</em>

5 0

3 years ago

9x2/3 help due in 3 min

sattari [20]

Answer:

Step-by-step explanation:

9/1 × 2/3

(9 × 2 = 18)

(1 × 3 = 3)

18 ÷ 3 = 6

7 0

3 years ago

8 entre 3 cuánto sobraría

a_sh-v [17]

Answer:

Step-by-step explanation:

,.............................

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3 years ago

Calculate the scale factor for the original triangle and its

Afina-wow [57]

Answer:

Step-by-step explanation:

8/4=2

have a good day..

3 0

3 years ago

PPLLEEAASSEE HHEELLPP

34kurt

We simply need to find a common denominator. The common denominator between the two (LCM/Least common multiple for denominator) is 24.

Now, we multiply the numerators also. We have our new numbers: 2 8/24 for October, 12/24 for November, and 3 9/24 for December. Now, we have to add them together. 2 8/24 + 12/24 = 2 20/24

Now, add the December value to the combined October/November values.

2 20/24 + 3 9/24 = 5 29/24

Now, we need to simplify the fraction.

6 9/24

Answer: 6 3/8 inches of rain occured in the three months.

8 0

3 years ago