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densk [106]
3 years ago
6

Find the values of k such that the equation kx^2-x-1 = 0 has no real roots

Mathematics
1 answer:
stich3 [128]3 years ago
3 0
Kx^2-x-1=0
Kx^2-x=1
Kx^2=1+x
K=1+x/x^2
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Answer:

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Step-by-step explanation:

First, let's find values for x which start is a -2 and end with a 2.

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Now we can find the y value by multiplying each term by 20.

-22 --> -440

-222 --> -4440

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Step-by-step explanation:

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