Answer:
It was ((A))...NOT ((D))!!!
Step-by-step explanation:
You need to use y=mx+b to solve the equation.
Answer:
your anserw is 1,300
Step-by-step explanation:
please rate me the branlest
Let x be the amount she invested in the 7% interest account
let y be the amount she invested in the 6% interest account
assume linda spent all of her allocated interest money in investment, so x and y must add up to 30000
x + y = 30 000
interest equation:
interest = (investment )· (interest rate)· (time)
interest rate is the decimal percentage form.
the time for both accounts is one year because the only info we're given as amount of total interest from both accounts after one year.
interest from the 7% account
= x(0.07)(1)
= 0.07x
interest from the 6% account
= y(0.06)(1)
= 0.06y
The total interest is 1970. Therefore
interest from the 7% account + interest from the 6% account = 1970
0.07x + 0.06y = 1970
system of equations
x + y = 30 000 ........... (I)
0.07x + 0.06y = 1970 ............ (II)
solve by elimination.
multiply both sides of equation (I) by -0.07
we do this so that we can get rid of 0.07x in equation (II)
-0.07x - 0.07y = -2100 ........... (I')
add equations (II) and this altered equation (I') together
0.07x + 0.06y = 1970 ...... (II)
+ -0.07x - 0.07y = -2100 ...... (I')
-----------------------------------
0x - 0.01y = -130
y = -130 / -0.01
y = $13 000
use x + y = 30 000 to find x.
x + y = 30 000
x + 13 000 = 30 000
x = 30 000 - 13 000
x = $17000
since x is the amount she invested in the 7% interest account and y is the amount she invested in the 6% interest account
invested $17000 in the 7% account
invested $13000 in the 6% account
Answer:
Step-by-step explanation:
p = 0.05 ( or 5%)
n = 12
Part b)
Expected value = n X p
expected value = 12 X 0.05
Expected value = 0.60
Part c)
Batch will be accepted if the number of defectives is less than 2
P(accepted) = P( x = 0) + P (x = 1)
where x = number of defectives
From binomial formula;
P(X=x) = nCx X p^x X (1-p)^(n-x)
we got n = 12, p = 0.05
P(x=0) = 12C0 X 0.05^0 X (0.95)^12
P(x=0) = 0.54036
P(x=1) = 12C1 X (0.05)61 X (0.95)^11
P(x=1) = 0.34128
P(accepted) = 0.54036 + 0.34128
P(accepted) = 0.88164
Part d)
Standard deviation = √(0.05 X 0.95/12) = 0.062915