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ziro4ka [17]
2 years ago
11

The revenue from selling x necklaces is r(x) =10x. The cost of buying x necklaces is c(x)=4x+15. The profit from selling x neckl

aces is p(x)=r(x)-c(x).
Mathematics
2 answers:
Cerrena [4.2K]2 years ago
7 0

Answer:

the revenue is 280 by 190

blondinia [14]2 years ago
5 0

Answer: 280 by 190 is the revenue, hope this helps

You might be interested in
500
Rainbow [258]

Options

(A)350 (B)375 (C)725 (D)750 (E)775

Answer:

(E)775

Step-by-step explanation:

From the attached graph

In Year 5

  • 100 shares in ODX Group, Inc. was worth $175
  • 100 shares in Peer Comms Ltd was worth $200

Therefore the Cost of 100 shares in ODX Group, Inc. and 300 shares in  Peer Comms Ltd, in Year 5

=175+3(200)

=175+600

=$775

The correct option is E.

3 0
3 years ago
Problem type join results unknown
Allisa [31]

<u>Not sure what you are asking for, but,</u>

<u>Here is an example of a JRU (Join Result Unknown)  word problem</u>:

There were _____ kids on the playground. ____ more kids came onto the playground. How many kids are on the playground?

<u>Here is an example of a JCU (Join Change Unknown)  word problem:</u>

There were ____ kids on the playground. Some more kids came on the playground. Now there are ____ kids on the playground. How many kids came on the playground?

<u> Here is an example of a JSU (Join Start Unknown)  word problem:</u>

Some kids were on the playground. ____ kids came on the playground. Now there are ____ kids on the playground. How many kids were on the playground at the beginning?



8 0
3 years ago
A catering service offers
Fiesta28 [93]

Answer:

There are 52920 ways to do the banquet

Step-by-step explanation:

* Lets revise the combination to solve this problem

- A combination is a collection of the objects where the order

 doesn't matter

- The order is not important in this problem, so we can use the  

  combination nCr to find how many ways can this done

* Lets solve the problem

- A catering service offers 6 appetizers, 7 main courses, 10 desserts.

- A customer is to select 5  appetizers,  4  main courses, 5  desserts

 for a banquet

∵ We want to select  5  appetizers from 6

∴ There are 6C5 ways to chose the appetizers

∵ 6C5 = 6

∴ There are 6 ways to chose the appetizers

∵ We want to select  4  main courses from 7

∴ There are 7C4 ways to chose the main courses

∵ 7C4 = 35

∴ There are 35 ways to chose the main courses

∵ We want to select  5  desserts from 10

∴ There are 10C5 ways to chose the desserts

∵ 10C5 = 252

∴ There are 252 ways to chose the desserts

- To find the number of ways to do the banquet multiply all the

  answers above

∵ The total ways = 6C5 × 7C4 × 10C5

∴ The total ways = 6 × 35 × 252 = 52920

* There are 52920 ways to do the banquet

5 0
3 years ago
If f(x)= 2x-7, what is the equation for f^-1(x)
Citrus2011 [14]
F^-1(x)= (x+7)/2
it's the inverse so adding is subtracting and multiplication is divison
4 0
3 years ago
Determine algebraically whether the function is even, odd, or neither even nor odd.
m_a_m_a [10]
For a function (fn) to be odd:
f(x) = - f(-x)
For a fn to be even:
f(x) = f(-x)
For a fn to be neither even nor odd
f(x) != f(-x)  [No Relation]

(-x)^n = x^n   for n -> even
(-x)^n = -x^n  for n -> odd
In your example:

f(x) = -4x^3 + 4x
f(-x) = -4 (-x)^3 + 4 (-x)^1  ( 3 and 1 are odd powers )
f(-x) = 4x^3 - 4x   (take -1 common to do the check)
f(-x) = -( -4x^3 + 4x ) = - f(x)  [between the bracket was the original fn]

f(x) = - f(-x)   
so the function is odd also called symmetric about the origin
7 0
3 years ago
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