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Delvig [45]
3 years ago
6

Verify that 1.5, 5 is a solution to 2x-y=-1​

Mathematics
2 answers:
ehidna [41]3 years ago
4 0

Answer:

No the answer is incorrect

Step-by-step explanation:

2*1.5-5=-1

3-5=-1

-2=-1

-1 and -2 are not the same

The correct answer is 2,5

pav-90 [236]3 years ago
3 0

Place the x (1.5) and y (5) values into the equation, and solve. If the statement you get is true, it is a solution.

2x - y = -1​

2(1.5) - 5 = -1​

3 - 5 = -1

-2 ≠ -1

Since this is a false statement, negative 2 is not equal to -1, the ordered pair is NOT a solution. I hope this helps and have a great day!

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Answer:

This is an equation. Solutions: x=1.

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A researcher reports survey results by stating that the standard error of the mean is 25 the population standard deviation is 40
bezimeni [28]

Answer:

a) A sample of 256 was used in this survey.

b) 45.14% probability that the point estimate was within ±15 of the population mean

Step-by-step explanation:

This question is solved using the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

a. How large was the sample used in this survey?

We have that s = 25, \sigma = 400. We want to find n, so:

s = \frac{\sigma}{\sqrt{n}}

25 = \frac{400}{\sqrt{n}}

25\sqrt{n} = 400

\sqrt{n} = \frac{400}{25}

\sqrt{n} = 16

(\sqrt{n})^2 = 16^2[tex][tex]n = 256

A sample of 256 was used in this survey.

b. What is the probability that the point estimate was within ±15 of the population mean?

15 is the bounds with want, 25 is the standard error. So

Z = 15/25 = 0.6 has a pvalue of 0.7257

Z = -15/25 = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

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3 0
3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Answer:

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