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worty [1.4K]
3 years ago
13

13. What values of x satisfy the inequality 4x + 2 > 10? * What is the answer

Mathematics
2 answers:
mojhsa [17]3 years ago
4 0

Answer:

Hi! The answer to your question is x > 2

Step-by-step explanation:

☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆

☆Brainliest is greatly appreciated!☆

Hope this helps!!

- Brooklynn Deka

Genrish500 [490]3 years ago
4 0

Answer:

x > 2

Step-by-step explanation:

Treat this like an equation:

4x + 2 > 10 is like 4x + 2 = 10

so minus 2

4x= 10-2

4x = 8

divide by 4

x = 2 but write in format as the question says

x > 2

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All the numbers between 30 and 60 that are multiples of 8
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Question 9 (10 points)<br> Solve for x,<br> 2(x - 1) + 4 = 4(x + 1)
Nutka1998 [239]
1. Expand
2x − 2 + 4 = 4x + 4

2. Simply
2x + 2 = 4x + 4

3. Subtract
2 = 4x + 4 - 2x

4. Simplify
2 = 2x + 4

5.Subtract
2 - 4 = 2x

6. Simplify
-2 = 2x

7. Divide both sides by
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6 0
3 years ago
Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experime
Citrus2011 [14]

Answer:

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

Step-by-step explanation:

We have to perform a hypothesis test on the difference between means.

The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2

μ1: mean heat output for subjects with the syndrome.

μ2: mean heat output for non-sufferers.

We will use a significance level of 0.05.

The difference between sample means is:

M_d=\bar x_1-\bar x_2=0.63-2.09=-1.46

The standard error is

s_{M_d}=\sqrt{\sigma_1^2/n_1+\sigma_2^2/n_2}=\sqrt{0.3^2/9+0.5^2/9}=\sqrt{ 0.038 } \\\\ s_{M_d}=0.194

The t-statistic is

t=\dfrac{M_d}{s_{M_d}}=\dfrac{-1.46}{0.194}=-7.52

The degrees of freedom are

df=n_1+n_2-2=9+9-2=16

The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.

The t-statistic is below the critical value, so it lies in the rejection region.

The null hypothesis is rejected.

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

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3 years ago
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I hope this helps you

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