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icang [17]
2 years ago
10

On January 22 in 1943, the town of Spearfish, South Dakota, set the record for the world’s fastest temperature change. At 7:30 a

.m., the temperature was −4°F. By 7:32 a.m., the temperature was 45°F. By 9:00 a.m. the same day, the temperature was 54°F. By 9:27 a.m., the temperature was −4°F. What is the difference between the temperature at 7:30 and the temperature at 9:27? Make sure to show whether the change was positive or negative.
Mathematics
2 answers:
Maru [420]2 years ago
7 0

Answer:

Nothing Changed

Step-by-step explanation:

at 7:30 it was −4°F and at 9:27 it was still −4°F.
However in-between the timelines +58° then it went down 58°

makvit [3.9K]2 years ago
6 0

Answer:

Nothing changed, so 0.

Step-by-step explanation:

The temperature went up 58 degrees and then was down 58 degrees by 9:27.

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2 1/2 times (-3 3/4)
serious [3.7K]

Answer:

-9.375

Step-by-step explanation:

2 1/2 x (-3 3/4) = -9.375

3 0
2 years ago
Read 2 more answers
Can someone please help me with this question about given two points?Please help ASAP!!! :(
KonstantinChe [14]

Answer:

<em>The order of subtraction is not important in any of the coordinates</em>

Step-by-step explanation:

Distance Between Two Points

Given two points (x1,y2) (x2,y2), the distance between them is given by the formula

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The difference between both coordinates is squared, then added, and finally extracted the square root.

Based on the principle that

a*a=a^2

and also

(-a)(-a)=a^2

We can notice it doesn't matter the sign of a the square of a is always positive. If we had subtracted in the opposite way, the distance would have resulted in exactly the same. In other words, the above formula is exactly the same as

d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

As seen, it applies for both coordinates

6 0
2 years ago
Two kilograms of bronze costs £7.20<br> What is the cost of 300g of bronze
sineoko [7]
We know that
1 Kg is equals to--------------> 1000 g
so
 X Kg------------------------> 300 g
X=300/1000------> x=0.30 Kg

if  2 Kg cost--------------> <span>£7.20
  0.30 Kg-------------> X
X=0.30*7.20/2------> x=1.08

the answer is 
</span>£1.08
3 0
3 years ago
(x+2)(x-3)(x+5) is identical to x^(3)+ax^(2)-11x+b<br> Find the value of a and the value of b
lutik1710 [3]

Answer:

a = 4 and b = - 30

Step-by-step explanation:

Expand the left side and compare like terms on both sides, that is

(x + 2)(x - 3)(x + 5) ← expand the first pair of factors using FOIL

= (x² - x - 6)(x + 5) ← distribute

= x³ + 5x² - x² - 5x - 6x - 30 ← collect like terms

= x³ + 4x² - 11x - 30

Compare like terms with x³ +ax² - 11x + b

4x² and ax² ⇒ a = 4

+ b and - 30 ⇒ b = - 30

3 0
3 years ago
Solve y′′=sin(x) if y(0)=0 and y′(0)=5.<br><br> y(x)=?
Ksenya-84 [330]

Answer:

y(x)=6x-sin(x)

Step-by-step explanation:

Rewrite the differential equation as:

\frac{d^{2} y }{dx^{2} } =sin(x)

Integrate both sides with respect to x:

\int\ \frac{d^{2} y }{dx^{2} } dx = \int\ sin(x) dx

\frac{dy}{dx} =-cos(x)+C_1

Integrate one more time both sides with respect to x:

\int\ \frac{dy}{dx} = \int\ -cos(x)+C_1 dx

y(x)=-sin(x)+C_1x+C_2

Now that we find the solution, let's find its derivate:

y'(x)=C_1-cos(x)

Evaluating the initial conditions:

y(0)=C_1(0)+C_2-sin(0)=0\\C_2=0

y'(0)=C_1-cos(0)=5\\C_1=5+1=6

Replacing the value of the constants that we found in the differential equation solution:

y(x)=6x-sin(x)

6 0
3 years ago
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