Answer:
(10^11)/3
10^6 x 10^5 = 10^11
8/5 x 5/24 = 1/3
so multiply 10^11 and 1/3 together
Answer:
option 4.
16 square units
Step-by-step explanation:
as we do not have the measures of the sides, but if the points of the vertices with Pythagoras we can calculate the sides.
P = (2 , 4)
S = (4 , 2)
we have to subtract the values of p from s
PS = (4 - 2 , 2 - 4)
PS = (2 , -2)
by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2
h: hypotenuse
c1: leg 1
c2: leg 2
PS^2 = 2^2 + -2^2
PS = √ 4 + 4
PS = √8
PS = 2√2
S = (4 , 2)
R = (8 , 6)
SR = (8-4 , 6-2)
SR = (4 , 4)
by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2
h: hypotenuse
c1: leg 1
c2: leg 2
SR^2 = 4^2 + 4^2
SR = √ (16 + 16)
SR = √32
SR = 4√2
having the values of 2 of its sides we multiply them and obtain their area
PS * RS = Area
2√2 * 4√2 =
16
Answer:
(5x-8)(x-2)
Step-by-step explanation:
or either use quadratic formula
Answer:
(1,4),(2,12)
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The form is y = ab^x
12 = ab^2
4 = ab^1
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Divide the 1st by the 2nd to get:
3 = b
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Substitute that into the 2nd equation to solve for "a":
4 = a*3^1
a=(4/3)
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EQUATION:
y = (4/3)*2^x
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Step-by-step explanation:
