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2 years ago

Determine whether or not the given value is a solution for the equation. Answer Yes or No

1 answer:

5 0

Y=24 is a solution for the equation.

y/12=2 is solved by multiplying both sides by 12 to get y by itself. so you'd end up multiplying 2 • 12 which equals 24.

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Find an ordered pair x,y 4x-y=5

allochka39001 [22]

y=2X-5 and 4X-Y=7

Putting the value of Y in 2nd equation:

4x-2x+5=7

2x=7-5

2x=2

OR,x=2/2=1

putting the value of x in equation 1:

y=2x-5

y=2*1-5

y=2-5

y=-3

6 0

2 years ago

Rachel and Hugo sorted 236 crayons into boxes for a local arts project. Each box had 10 crayons. How many crayons were left over

yarga [219]

230/10 = 23 with no remainder.
236/10 = 23 with remainder 6.
6 crayons were left over.

5 0

3 years ago

The floor of a rectangular cage has a length 4 feet greater than its width, w. James

guajiro [1.7K]

Answer:

x² + 8x + 12

Step-by-step explanation:

Area of a rectangle = length × width

Original dimensions:

Width = x

Length = x + 4

James will increase both dimensions of the floor by 2 feet

New dimensions:

Width = x + 2

Length = x + 4 + 2

= x + 6

Area of the new rectangle = length × width

= (x + 2) × (x + 6)

= x² + 6x + 2x + 12

= x² + 8x + 12

Equation which represents the

new area, N, of the floor of the cage = x² + 8x + 12

3 0

2 years ago

Express this to single logarithm

zzz [600]

Answer: $\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)$

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

log(A) + log(B) = log(A*B)
log(A) - log(B) = log(A/B)
B*log(A) = log(A^B)

From there, we can then say the following:

$\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}$

8 0

2 years ago

Please help me with B im stuck

Margarita [4]

Answer:

A = 160

Step-by-step explanation:

Formula 1/2 d1d2

1/2 (16 x 20)

320 x 1/2 OR 320/2

=160

Hope this helps :)

6 0

2 years ago