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sladkih [1.3K]
3 years ago
14

1/6 + 2/3 tell me wat it is pls​

Mathematics
2 answers:
guapka [62]3 years ago
8 0

Answer:

5/6

Step-by-step explanation:

you can rewrite 2/3 plus 1/6 as:

2/3+1/6

To add fractions you need to have a common denominator (the bottom half of the fraction). In this case 6 is a common denominator. To convert 2/3 we need to multiply it by the appropriate form of 1. We can multiply by 1 because 1 times anything does not change the value:

(2/2⋅2/3)+1/6⇒2/2⋅2/3+1/6⇒4/6+1/6⇒5/6

Nutka1998 [239]3 years ago
5 0

Answer: 5/6

Step-by-step explanation:

2/3=4/6

1/6 + 4/6 = 5/6

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Suck at fractions and simplifying
galina1969 [7]

Answer:

7

Step-by-step explanation:

2(3) + 6²/6

Multiply 2x3 and 6² is just multiplying 6x6

6+36/6

Add 6+36

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8 0
2 years ago
Read 2 more answers
¿Cuál es el volumen en pulgadas cúbicas de una esfera cuya circunferencia mide 64 pulgadas?
pochemuha

Answer:

4445.18 pulgadas cúbicas

Step-by-step explanation:

Paso 1

La fórmula para la circunferencia de una esfera = 2πr

Circunferencia de una esfera = 64 pulgadas

Por eso,

64 = 2πr

Por lo tanto, encontramos r

Dividir ambos lados por 2π

64 / 2π = 2πr / 2π

r = 10.185916358 pulgadas

Radio r = 10.2 pulgadas

Paso 2

Volumen de una esfera

= 4/3 × π × r³

r = 10.2 pulgadas

Por lo tanto, 4/3 × π × (10.2) ³

= 4445.18 pulgadas cúbicas

Por lo tanto, el volumen en pulgadas cúbicas de una esfera = 4445.18 pulgadas cúbicas

6 0
3 years ago
Which property of equality was used to solve this equation?
HACTEHA [7]
Division property of equality. They are dividing -5 to both sides.
3 0
3 years ago
The table below shows some input and output values for a function named F(n). Which of the following equations describes F(n)?
Klio2033 [76]
It looks like it would be C, but I'm not sure 
6 0
3 years ago
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nevsk [136]
. The series is divergent. To see this, first observe that the series ∑ 1/kn for n = 1 to ∞ is divergent for any integer k ≥ 2. 

Now, if we pick a large integer for k, say k > 100, then for nearly all integers n it will be true that 1 > cos(n) > 1/k. Therefore, since ∑ 1/kn is divergent, ∑ cos(n)/n must also be divergent The *summation* is divergent, but the individual terms converge to the number 0.<span>by comparison test since cosn/n <= 1/n is convergent and 1/n is divergent by harmonic series so the series is conditionally converget </span>
4 0
3 years ago
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