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2 years ago

Heyyy.... can someone pls help asap. Rearrange the formula to write r in terms of P and pi.

Mathematics

2 answers:

bearhunter [10]2 years ago

6 0

Step-by-step explanation:

p = 2r + pi×r

p = r(2 + pi)

r = p/(2 + pi)

8090 [49]2 years ago

6 0

Answer:

r = $\frac{p}{2+\pi }$

Step-by-step explanation:

p = 2r + πr ← factor out r from each term

p = r(2 + π) ← divide both sides by (2 + π )

$\frac{p}{2+\pi }$ = r

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Find the value of k if the distance between (2,k) and (6,7) is 4√2 unit

andreyandreev [35.5K]

Answer:

k = 3

Step-by-step explanation:

We have the distance formula: $d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$ . We can plug in $4\sqrt{2}$ = d, x2 = 6, x1=2, y2 = 7, y1 = k.

Then, we can solve the question using some algebra to find that k = 3.

Edit: Here is a step by step:

$4\sqrt{2} = \sqrt{(6-2)^2 + (7-k)^2}\\$

$(4\sqrt{2})^2 = (6-2)^2 + (7-k)^2$

$32 = (4)^2 + (7-k)^2$

$32 = 16 + (7-k)^2$

$32 - 16 = (7-k)^2$

$16 = (7-k)^2$

$\sqrt{16} = (7-k)$

$4 = 7-k$

$k = 3$

4 0

3 years ago

Suppose that farmer's grew an unexpectedly large number of tomatoes this year. How would this increase in production affect the

MArishka [77]

The price would decrease because they want to get rid of the tomatoes

5 0

3 years ago

Read 2 more answers

Algebra help?<br><br> 343 = (x/6) ^2/3

Vladimir79 [104]

I can only assume that you meant, "Solve for x:"

Apply the exponent 3/2 to both sides of this equation. The result will be

3/2

343 = x/6.

Multiplying both sides by 6 isolates x:

3/2

6*343 = x Since 7^3 = 343, the expression for x

can be rewritten as

3/2

6*(7^3) = x which can be further simplified, as follows:

x = 6^(3/2)*7^(9/2), or:

x = 6^(3/2)*7^(8/2)*√7, or

x = 6^(3/2)*7^4*√7

3 0

3 years ago

Calculate the specific heat of a metal (in calories/gram-degree C) from the following data. A container made of the metal has a

Arisa [49]

Answer:

<h2>The specific heat of the metal is 0.274951 calories/gram-degree C.</h2>

Step-by-step explanation:

Let, the specific heat of the container is x calories/gram-degree C.

The container and water gains (18 - 15) = 3 degrees C.

Hence, the transfer of heat is $3(18.1\times1000\times1) + 3(3.77x\times1000)$ .

The metal, which is dropped in the water, losses (164 - 18)= 144 degrees C.

Hence, the transfer of heat is $144\times 1.45\times1000x$ .

As per the given conditions,

$3(18.1\times1000) + 3(3.77x\times1000) = 144\times1.45\times1000x\\54.3 + 11.31x = 208.8x\\197.49x = 54.3\\x = 0.274951$ .

6 0

3 years ago

Solve for n.<br><br> 11(n – 1) + 35 = 3n<br><br> n = –6<br> n = –3<br> n = 3<br> n = 6

RSB [31]

Solve for n
Simply both sides 11(n-1)+35=3n
Distribute (11)(n) + (11)(-1) + 35 = 3n
11n+-11+35=3n
Combine like terms (11n)+(-11+35)=3n
11n + 24 =3n
Subtract 3n from both sides
11n+24-3n=3n-3n
8n + 24 = 0
Subtract 24 from both sides
8n+24-24=0-24
8n = -24
Divide both sides by 8
8n = -24
8 8
n = -3

6 0

2 years ago