Answer:
![36+27\pi\:\mathrm{in^2}](https://tex.z-dn.net/?f=36%2B27%5Cpi%5C%3A%5Cmathrm%7Bin%5E2%7D)
Step-by-step explanation:
The figure consists of a square and a sector. We can add the areas of the square and sector to get the total area of the figure.
The area of a sector with measure
in a circle of radius
is equal to
. Since there are 360 degrees in a circle and 90 degrees in each corner of a square, the measure of the sector is
.
Thus, its area is:
.
The area of a square with side length
is given by
. Therefore, the area of the circle is
and the total area of the figure is ![\boxed{36+27\pi\:\mathrm{in^2}}](https://tex.z-dn.net/?f=%5Cboxed%7B36%2B27%5Cpi%5C%3A%5Cmathrm%7Bin%5E2%7D%7D)
Can you write it out differently? I don't understand.
Answer:
The function is not defined for x=2
Step-by-step explanation:
we have
![\frac{1}{x-2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx-2%7D)
we know that
In a quotient the denominator cannot be equal to zero
so
equate the denominator to zero to find the value of x
![x-2=0](https://tex.z-dn.net/?f=x-2%3D0)
solve for x
![x=2](https://tex.z-dn.net/?f=x%3D2)
therefore
The function is not defined for x=2