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yan [13]
3 years ago
14

Need help with this have no idea how to do it

Mathematics
1 answer:
podryga [215]3 years ago
4 0

Answer:

Step-by-step explanation:

x- intercept, vertex (v) and axis of symmetry, parabola form:x²+bx+c

vertex(h,k)

<h2>1- f(x)=(x+3)(x-3) change into parabola form </h2>

f(x)=x²-9  a=1,b=0 ,c=-9

h=-b/2a=0

k=f(0)=-9

vertex(0,-9) , x intercept is when f(x)=0

(x-3)(x+3)=0 either x-3=0⇒ x=3 or x+3=0 then x=-3

x=3, x=-3 (-3,0) and (3,0)

the x of symmetry is the h of the vertex=0

<h2>2-g(x)=(x+1)(x-3)</h2>

g(x)=x²-2x-3 a=1, b=-2,c=-3

h=-b/2a⇒-(-2)/2(1)⇒h=1

k=f(1)=1²-2(1)-3⇒k=-4

v(1,-4)

x of symmetry=h=1

(x+1)(x-3)=0

x+1=0⇒x=-1 (-1,0)

x-3=0 ⇒x=3  (3,0)

x intercept :-1,3

<h2>3-y=-x(x+6) ⇒y=-x²-6x a=-1,b=-6, c=0</h2>

vertex(-3,9)

x intercept:(0,0) and (-6,0)

axis of symmetry =-3

<h2>4-g(x)=2(x-5)(x-1) ⇒ 2x²-12x+10 a=2, b=-12, c=10</h2>

vertex(3,-8)

axis of symmetry=3

x intercept : (5,0), (1,0)

<h2>5) -4x(x+1)⇒-4x²-4x a=-4,b=-4</h2>

vertex(-1/2,1)

x of symmetry=-1/2

x intercept : (0,0)(-1,0)

<h2>6- f(x)=-2(x-3)² ⇒-2x²+12x-18</h2>

vertex(3,0)

x intercept (3,0)

axis of symmetry = 3

<h2 /><h2 />

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Answer:

  Find the LCD of the first two, then the LCD of that and the third one.

Step-by-step explanation:

You can do it by finding the LCD of two of the denominators, then the LCD of that and the third denominator.

Or, you can factor each of the denominators and find their LCM by multiplying the unique factors to their highest powers.

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<u>Example:</u>

  1/21 + 1/35 + 1/45

The LCD of 1/21 and 1/35 is (21·35)/5 = 105. The LCD of 1/105 and 1/45 is ...

  (105·45)/15 = 315

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Using factoring ...

  • 21 = 3·7
  • 35 = 5·7
  • 45 = 3²·5

LCD = 3²·5·7 = 315

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9. Determine if x + 1 is a factor of x ^ 4 - 4x ^ 2 - 4x - 1 Justify your answer.
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2 years ago
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
3 years ago
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