Seven x's and 3y's cost as much as 4z's. One z costs as much as 1x plus 1y together. How many x's cost as much as 1y?
1 answer:
Answer:
Step-by-step explanation:
Equations
7x + 3y = 4z
<em>Second equation</em>
x + y = z Multiply the entire equation by 4
4[x + y = z] Now distribute the 4 through the equation
4x + 4y = 4z Both equations = 4z. Equate the lefts.
<em>Third equation </em>
7x+3y = 4x + 4y Subtract 3y from both sides
7x + 3y -3y = 4x + 4y -3y
7x = y + 4x Subtract 4x from both sides
7x - 4x = y + 4x - 4x Combine
3x = y
Answer: 3x = y
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Step-by-step explanation:
the dot filled in means that its equal to 12 and above
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Answer:
7x
Step-by-step explanation:
9x-2x=7x
45/100
Simplify the fraction by diving by the largest possible factor
45 divided by 5 = 9
100 divided by 5 = 20
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9/20 = 0.45
The roots of x^{2} 6x-55=0 the answer is going to be
the roots is going to 3[1980/6}
x= 2.09284539
Answer:
20
Step-by-step explanation:
4:4,8,12,16,20
5,5,10,15,20
20 is the frist number u come to when multiplying by your 4s and 5s
