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Mariana [72]
2 years ago
6

Seven x's and 3y's cost as much as 4z's. One z costs as much as 1x plus 1y together. How many x's cost as much as 1y?

Mathematics
1 answer:
Pie2 years ago
6 0

Answer:

Step-by-step explanation:

Equations

7x + 3y = 4z

<em>Second equation</em>

x + y = z                          Multiply the entire equation by 4

4[x + y = z]                      Now distribute the 4 through the equation

4x + 4y = 4z                    Both equations = 4z. Equate the lefts.

<em>Third equation   </em>

7x+3y = 4x + 4y              Subtract 3y from both sides

7x + 3y -3y = 4x + 4y -3y

7x = y + 4x                      Subtract 4x from both sides

7x - 4x = y + 4x - 4x       Combine

3x = y

Answer: 3x = y

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(x+2)2+(9-3)2=4, the radius of the circle is...
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3 years ago
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8 0
3 years ago
I need the answer for number 6 please:)
Goshia [24]

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and so does

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