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Mariana [72]
2 years ago
6

Seven x's and 3y's cost as much as 4z's. One z costs as much as 1x plus 1y together. How many x's cost as much as 1y?

Mathematics
1 answer:
Pie2 years ago
6 0

Answer:

Step-by-step explanation:

Equations

7x + 3y = 4z

<em>Second equation</em>

x + y = z                          Multiply the entire equation by 4

4[x + y = z]                      Now distribute the 4 through the equation

4x + 4y = 4z                    Both equations = 4z. Equate the lefts.

<em>Third equation   </em>

7x+3y = 4x + 4y              Subtract 3y from both sides

7x + 3y -3y = 4x + 4y -3y

7x = y + 4x                      Subtract 4x from both sides

7x - 4x = y + 4x - 4x       Combine

3x = y

Answer: 3x = y

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Help me with area, please.
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Answer:

Num. 2: A = 25, Num. 3 = 63, Num. 4 = 80

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I'll help with as many as I can, so a few of them I won't be able too answer. You should re-post those later. Good luck, hope this helps.

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First, turn the triangle into a rectangle by cutting it in half and attaching it to the other half so it forms a rectangle.

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The area for number 2 is 25.

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