Multiply everything by 2 then combine like terms
Y = mx + b
slope(m) = -3/4
(3,3)....x = 3 and y = 3
now we sub and find b, the y int
3 = -3/4(3) + b
3 = -9/4 + b
3 + 9/4 = b
12/4 + 9/4 = b
21/4 = b.....or 5.25 for graphing purposes
so ur equation is : y = -3/4x + 21/4
ur y int = (0,21/4) or (0,5.25)
ur x int can be found by subbing in 0 for y and solving for x
y = -3/4x + 21/4
0 = -3/4x + 21/4
3/4x = 21/4
x = 21/4 * 4/3
x = 84/12 = 7.....so ur x int is (7,0)
so plot ur points (7,0) and (0,5.25)....now start at (0,5.25) and since the slope is -3/4, come down 3 spaces and go to the right 4 spaces, then down 3, and to the right 4 and u will eventually cross the x axis at (7,0)
Hey!
Let's write it,

Add

to both sides,


Subtract

from both sides.


Since we don't want a negative variable, we have to divide both sides by

.

Our answer would be,

Thanks!
-TetraFish
Answer:
<em>Option A, Option C, Option E</em>
Step-by-step explanation:
The area of a kite can be identified through 1 / 2 of the multiplication of each diagonal. The first diagonal is equivalent to the addition of 50 cm and 10 cm, while the second is of length 20 cm + 20 cm.

Consider the first option. If we take a look at the bit 2 * ( 1 / 2 * 20 * 50 ) the 2 and 1 /2 cancel each other out, leaving you with 20 * 50 = 1000 . Respectively in the expression 2 * ( 1 / 2 * 20 * 10 ) the 2 and 1 / 2 cancel each other out, leaving you with 20 * 10 = 200;

The second option considers the expression 2 * ( 1 / 2 * 20 * 60 ). Again, the 2 and 1 / 2 cancel each other out, leaving you with 20 * 60;

Option C is a similar version of option a, besides the fact that the 1 / 2 doesn't exist. Thus, Option C is incorrect!
Option D is a similar version of option a as well, but as the 2 doesn't exist, it is incorrect!
This last option, option E is taken as 1 / 2 of the multiplication of the diagonals, and thus is correct!
