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ICE Princess25 [194]
1 year ago
5

Find the 14 term of the following geometric sequence. 10, 20, 40, 80,

Mathematics
2 answers:
MA_775_DIABLO [31]1 year ago
8 0

Answer:

the 14th term in the sequence would be 81920.

Step-by-step explanation:

because you are multiplying by 2 each time to find the next multiply 80 by 2 giving you 160 again giving you 320 again giving you 640 than 1280 , 2560 ,5120 ,10240 ,20480 ,40960 ,finally the 14th number in the sequence multiplying 40960 by 2 would give you your answer of 81920.

vagabundo [1.1K]1 year ago
4 0

Answer:

<u>81920</u>

Step-by-step explanation:

Finding the common ratio (r) :

  • 20/10
  • 2

Finding the 14th term :

  • a₁₄ = ar¹⁴⁻¹
  • a₁₄ = ar¹³
  • a₁₄ = (10)(2)¹³
  • a₁₄ = (10)(8192)
  • a₁₄ = <u>81920</u>
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A box of 42 jelly beans contains 9 orange jelly beans. What is the probability that a randomly selected jelly bean will be orang
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3 years ago
an outlier may be defined as a data point that is more than 1.5 times the interquartile range below the lower quartile or is mor
Ira Lisetskai [31]

Supposing a normal distribution, we find that:

The diameter of the smallest tree that is an outlier is of 16.36 inches.

--------------------------------

We suppose that tree diameters are normally distributed with <u>mean 8.8 inches and standard deviation 2.8 inches.</u>

<u />

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • The Z-score measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.<u> </u>

<u />

In this problem:

  • Mean of 8.8 inches, thus \mu = 8.8.
  • Standard deviation of 2.8 inches, thus \sigma = 2.8.

<u />

The interquartile range(IQR) is the difference between the 75th and the 25th percentile.

<u />

25th percentile:

  • X when Z has a p-value of 0.25, so X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 8.8}{2.8}

X - 8.8 = -0.675(2.8)

X = 6.91

75th percentile:

  • X when Z has a p-value of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 8.8}{2.8}

X - 8.8 = 0.675(2.8)

X = 10.69

The IQR is:

IQR = 10.69 - 6.91 = 3.78

What is the diameter, in inches, of the smallest tree that is an outlier?

  • The diameter is <u>1.5IQR above the 75th percentile</u>, thus:

10.69 + 1.5(3.78) = 16.36

The diameter of the smallest tree that is an outlier is of 16.36 inches.

<u />

A similar problem is given at brainly.com/question/15683591

3 0
2 years ago
Easy % question with adding
Alchen [17]

Answer:

17.00

Step-by-step explanation:

So first you have to add 12.35 to 7.5% which equals 13.27625.

Then you round 13.27625 to the nearest 0.01 or hundredths place and that gives you 13.28.

Then you add 25% to 13.28 and that gives you 16.6 and if you round 16.6 you get 17.00.

I hope I helped! Please give a Rate and Thanks.

7 0
2 years ago
Read 2 more answers
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