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2 years ago

Find the 14 term of the following geometric sequence. 10, 20, 40, 80,

Mathematics

2 answers:

MA_775_DIABLO [31]2 years ago

8 0

Answer:

the 14th term in the sequence would be 81920.

Step-by-step explanation:

because you are multiplying by 2 each time to find the next multiply 80 by 2 giving you 160 again giving you 320 again giving you 640 than 1280 , 2560 ,5120 ,10240 ,20480 ,40960 ,finally the 14th number in the sequence multiplying 40960 by 2 would give you your answer of 81920.

vagabundo [1.1K]2 years ago

4 0

Answer:

81920

Step-by-step explanation:

Finding the common ratio (r) :

20/10
2

Finding the 14th term :

a₁₄ = ar¹⁴⁻¹
a₁₄ = ar¹³
a₁₄ = (10)(2)¹³
a₁₄ = (10)(8192)
a₁₄ = 81920

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see the draw in the attached figure N 1

case 2) For x=32 units

substitute in the equation 1

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see the draw in the attached figure N 2

case 3) For x=16 units

substitute in the equation 1

$x*y=64$

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see the draw in the attached figure N 3

case 4) For x=30 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/30$

$y=\frac{32}{15} =2\frac{2}{15} \ units$

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see the draw in the attached figure N 4

case 5) For x=40 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/40$

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see the draw in the attached figure N 5

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substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/60$

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