All categories

3 years ago

Can someone help me please

Mathematics

1 answer:

Vesnalui [34]3 years ago

8 0

Answer:

Step-by-step explanation:

for the rectangles you use the formula :

a=lw 3x6=18x2=36 + 4x6=24

and for the triangles you use:

a=1/2bh 3x4=12/2 + 3x4=12/2

then you add it all together

36+24+12=72

You might be interested in

True or false (picture provided)

Kitty [74]

Answer:

True

Step-by-step explanation:

we know that

A non-negative number is a real number greater than or equal to zero

In this problem

we have

$x\geq 0$

The solution of the inequality is all real numbers greater than or equal to zero [0,∞)

Therefore

$x\geq 0$ express a non-negative number in symbols

3 0

3 years ago

Please help me with this questionnn

Llana [10]

Answer:

V = 1436.76

Step-by-step explanation:

Formula:

V = 4/3πr³

Given:

r = 7

Work:

V = 4/3πr³

V = 4/3π(7³)

V = 4/3π(343)

V = 1436.76

6 0

3 years ago

How to graph the function f(x)=-2(x+3) +4

Paraphin [41]

Answer:

Step-by-step explanation:

first of all, simplify your fraction. f(x)= -2(x+3) + 4

f(x)= (-2x-6) + 4

f(x)= -2x-2

y intercept is -2 and the slope is -2, go down 2 and right 1

3 0

3 years ago

What percentage of the general U.S. population have bachelor's degrees? The Statistical Abstract of the United States, 120th Edi

Bess [88]

Answer:

a) Figure attached

b) $Q_1 = \frac{22+22}{2}= 22$

$Q_3 = \frac{27+27}{2}= 27$

$IQR = Q_3 -Q_1= 27-22 =5$

c) between the median and Q3

Step-by-step explanation:

For this case we have the following data:

17 18 18 18 19 20 20 20 21 21 21 21 22 22 22 22 22 22 23 23 24 24 24 24 24 24 24 24 25 26 26 26 26 26 26 27 27 27 27 27 28 28 29 31 31 32 32 34 35 38

Part a

We can construct the boxplot with the following R code:

> x<-c(17, 18, 18, 18, 19, 20, 20, 20, 21 ,21, 21, 21, 22, 22, 22, 22, 22, 22, 23, 23, 24, 24, 24, 24, 24, 24, 24, 24, 25, 26, 26, 26, 26, 26, 26, 27, 27, 27, 27, 27, 28, 28, 29, 31, 31, 32, 32, 34, 35, 38)

> boxplot(x,main="Boxplot of data")

> summary(x)

Min. 1st Qu. Median Mean 3rd Qu. Max.

17.00 22.00 24.00 24.76 27.00 38.00

The results are on the figure attached.

The mean >Median so then we can conclude that the distribution is slightly skewed to the right.

Part b

For this case since we have 50 data values in order to find the the Q1 we use the following values 17, 18, 18, 18, 19, 20, 20, 20, 21 ,21, 21, 21, 22, 22, 22, 22, 22, 22, 23, 23, 24, 24, 24, 24, 24, 24

And the Q1 would be the average between position 13 and 14 and we got:

$Q_1 = \frac{22+22}{2}= 22$

For the Q3 we need to use the following data values: 24, 24, 24, 24, 25, 26, 26, 26, 26, 26, 26, 27, 27, 27, 27, 27, 28, 28, 29, 31, 31, 32, 32, 34, 35, 38

And the Q3 would be the average between position 13 and 14 and we got:

$Q_3 = \frac{27+27}{2}= 27$

So then $IQR = Q_3 -Q_1= 27-22 =5$

Part c

For this case we have a value of 26 and if we see this value is between the meadian and Q3 since the median = 24 and Q3 = 27

between the median and Q3

4 0

4 years ago

Evaluate f(x)=5x- 9 at the given value of x. f(8) f(8)=

zavuch27 [327]

Answer:

f(8) = 31

Step-by-step explanation:

To evaluate f(8) substitute x = 8 into f(x)

f(8) = (5 × 8) - 9 = 40 - 9 = 31

5 0

3 years ago