A rectangular auditorium seats 1564 people. the number of seats in each row exceeds the number of rows by 1212. find the number
1 answer:
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Answer:
(a)Cat
(b)8 animals
(c)6 people
Step-by-step explanation:
From the attached diagram:
Let the be x.
Half of =x/2
From the pictogram, we then have:
Therefore:
So we have the following numbers
(a)Cat was the least popular
(b) represents 8 animals
(c)
Number of People who preferred giraffe=20
Number of People who preferred dogs=14
Difference=20-14=6
Therefore, 6 more people preferred giraffes than dogs.
The volume of the cylinder is V = πr<span>²h.
For a circumscribed cylinder, we know that in a circumscribed cylinder, the height of a cylinder is twice of its radius as shown in the figure. So,
V = </span>πr²(2r) = 2πr<span>³
</span>Finally,
1458π = 2πr³
r³ = 729
r = 9 cm
That is the answer. Hope this helps <span>✌️</span>☺️✌️
For a circumscribed cylinder, we know that in a circumscribed cylinder, the height of a cylinder is twice of its radius as shown in the figure. So,
V = </span>πr²(2r) = 2πr<span>³
</span>Finally,
1458π = 2πr³
r³ = 729
r = 9 cm
That is the answer. Hope this helps <span>✌️</span>☺️✌️
Answer:
1. H0 : p = 0.9
H1 : p ≠ 0.9
2. The test is two tailed.
3. Reject the null hypothesis
Step-by-step explanation:
We are given that we have to test the claim that the proportion of people who own cats is significantly different than 90% at the 0.1 significance level.
So, Null Hypothesis, : p = 0.90
Alternate Hypothesis, : p
0.9
Here, the test is two tailed because we have given that to test the claim that the proportion of people who own cats is significantly different than 90% which means it can be less than 0.90 or more than 0.90.
Now, test statistics is given by;
~ N(0,1) , where, n = sample size = 100
= 0.94 (given)
So, Test statistics = = 1.68
Now, P-value = P(Z > 1.68) = 1 - P(Z <= 1.68)
= 1 - 0.95352 = 0.0465 ≈ 0.05 or 5%
Now, our decision rule is that;
If p-value < significance level ⇒ Reject null hypothesis
If p-value > significance level ⇒ Accept null hypothesis
Since, here p-value is less than significance level as 0.05 < 0.1, so we have sufficient evidence to reject null hypothesis.
Therefore, we conclude that proportion of people who own cats is significantly different than 90%.