Question

Flying against the wind, an airplane travels 2520 kilometers in 4 hours. Flying with the wind, the same plane travels 9450 kilometers in 9 hours. What is the rate of the plane in still air and what is the rate of the wind?

Answer 1

Using the relation between velocity, distance and time, it is found that:

• The rate of the plane is of 840 km/h.

• The rate of the wind is of 210 km/h.

What is the relation between velocity, distance and time?

Velocity is distance divided by time, that is:

$v = \frac{d}[t}$

Flying against the wind, an airplane travels 2520 kilometers in 4 hours, that is:

$v - v_w = \frac{2520}{4}$

$v - v_w = 630$

$v = 630 + v_w$

Flying with the wind, the same plane travels 9450 kilometers in 9 hours, hence:

$v + v_w = \frac{9450}{9}$

$v + v_w = 1050$

$v = 1050 - v_w$

Hence, solving for the wind's speed:

$630 + v_w = 1050 - v_w$

$2v_w = 420$

$v_w = \frac{420}{2}$

$v_w = 210$

For the plane, we have that:

v = 1050 - 210 = 840.

More can be learned about the relation between velocity, distance and time at brainly.com/question/24316569

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