Answer:
a) P=0.0225
b) P=0.057375
Step-by-step explanation:
From exercise we have that 15% of items produced are defective, we conclude that probabiity:
P=15/100
P=0.15
a) We calculate the probabiity that two items are defective:
P= 0.15 · 0.15
P=0.0225
b) We calculate the probabiity that two of three items are defective:
P={3}_C_{2} · 0.85 · 0.15 · 0.15
P=\frac{3!}{2!(3-2)!} · 0.019125
P=3 · 0.019125
P=0.057375
Answer:
4 more gallons of paint
Step-by-step explanation:
Answer:
yr answer is G. 21
<h2>stay safe healthy and happy<u>.</u><u>.</u></h2>
Is there more to this question or no?
When a researcher needs to compare means for a variable grouped into two
categories based on some less-than interval variable, a t-test is appropriate.
To add, The analysis of two populations means through the use of
statistical examination is called a t-test. Small sample sizes commonly
use a t-test with two
samples. <span> What statisticians call as test statistics are
identified as t-values. A systematized value that is calculated from sample
data during a hypothesis test is called a test statistic. The procedure that
calculates the test statistic compares your data to what is expected under the </span>null
hypothesis<span>.
You already have an experience with the basic principles behind a t-test if you’ve
tried to communicated with a distracted teenager.</span>
