Evaluate the expression. 2 • 15

What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7 ?

jarptica [38.1K]

The answer is $\frac{2}{3}$

4 0

2 years ago

Determine whether the triangle is a right triangle. Explain your reasoning. If it is not a right triangle, determine whether it

Alinara [238K]

Answer:

If it's Jose, Brad, and Ed it's an acute triangle, it has no 90 degree angle, if it's Jose, James, and Malcolm it is a right triangle because the line to Jose and Malcolm is straight I think not sure how to explain

Step-by-step explanation:

5 0

2 years ago

A cylindrical tank holds 352 cu. ft. of water. The height of the tank is 7 ft. Find the

Rzqust [24]

Answer:

0.3334 ft

Step-by-step explanation:

Measure the height and radius of the tank. The radius is the distance from the center of the tank to its outer edge. Another way to find the radius is to divide the diameter, or width, by two. Square the radius by multiplying the radius times itself and then multiply it by 3.1416, which is the constant pi.

Given height and volume: r = √(V / (π * h)),
Given height and lateral area: r = A_l / (2 * π * h),
Given height and total area: r = (√(h² + 2 * A / π) - h) / 2,
Given height and diagonal: r = √(h² + d²) / 2,
Given height and surface-area-to-volume ratio: r = 2 * h / (h * SA:V - 2),
Given volume and lateral area: r = 2 * V / A_l,
Given base area: r = √(A_b / (2 * π)),
Given lateral area and total area: r = √((A - A_l) / (2 * π)).

4 0

2 years ago

I dont understand how to do this precalc question

Alexeev081 [22]

Answer:

x-intercept: (-0.1, 0)
Horizontal Asymptote: y = -3
Exponential <u>growth</u>

(First answer option)

Step-by-step explanation:

<u>General form of an exponential function</u>

$y=ab^x+c$

where:

a is the initial value (y-intercept).
b is the base (growth/decay factor) in decimal form:
If b > 1 then it is an increasing function.
If 0 < b < 1 then it is a decreasing function.
y=c is the horizontal asymptote.
x is the independent variable.
y is the dependent variable.

Given <u>exponential function</u>:

$y=4(10)^x-3$

<h3><u>x-intercept</u></h3>

The x-intercept is the point at which the curve crosses the x-axis, so when y = 0. To find the x-intercept, substitute y = 0 into the given equation and solve for x:

$\begin{aligned}& \textsf{Set the function to zero}:& 4(10)^x-3 &=0\\\\& \textsf{Add 3 to both sides}:& 4(10)^x &=3\\\\& \textsf{Divide both sides by 4}:& 10^x &=\dfrac{3}{4}\\\\& \textsf{Take natural logs of both sides}:& \ln 10^x &=\ln\left(\dfrac{3}{4}\right)\\\\& \textsf{Apply the power log law}:&x \ln 10 &=\ln\left(\dfrac{3}{4}\right)\\\\& \textsf{Divide both sides by }\ln 10:&x&=\dfrac{\ln\left(\dfrac{3}{4}\right)}{\ln 10} \\\\& \textsf{Simplify}:&x&=-0.1\:\:\sf(1\:d.p.)\end{aligned}$

Therefore, the x-intercept is (-0.1, 0) to the nearest tenth.

<h3><u>Asymptote</u></h3>

An <u>asymptote</u> is a line that the curve gets infinitely close to, but never touches.

The <u>parent function</u> of an <u>exponential function</u> is:

$f(x)=b^x$

As<em> </em>x approaches -∞ the function f(x) approaches zero, and as x approaches ∞ the function f(x) approaches ∞.

Therefore, there is a horizontal asymptote at y = 0.

This means that a function in the form $f(x) = ab^x+c$ always has a horizontal asymptote at y = c.

Therefore, the horizontal asymptote of the given function is y = -3.

<h3><u>Exponential Growth and Decay</u></h3>

A graph representing exponential growth will have a curve that shows an <u>increase</u> in y as x increases.

A graph representing exponential decay will have a curve that shows a <u>decrease</u> in y as x increases.

The part of an exponential function that shows the growth/decay factor is the base (b).

If b > 1 then it is an increasing function.
If 0 < b < 1 then it is a decreasing function.

The base of the given function is 10 and so this confirms that the function is increasing since 10 > 1.

Learn more about exponential functions here:

brainly.com/question/27466089

brainly.com/question/27955470

6 0

1 year ago

A model rocket is launched straight into the air from platform 3 feet above the ground with an intial velocity of 192 feet per s

Pachacha [2.7K]

Answer:

Step-by-step explanation:

the function -16t^2 + 64t + 192 give the height S, in ft, of a model water rocket launched with a velocity of 64 ft/second from a hill that is 192 ft high. a) determine how long it will take the rocket to reach the ground, b) find the interval on which the height of the rocket is greater than 240 ft.

6 0

2 years ago

Evaluate the expression. 2 • 15 – 7 + 4