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Andru [333]
2 years ago
13

If two angles have the same angle measure, then they are said to be____.

Mathematics
2 answers:
Sergio [31]2 years ago
4 0

Answer:

C

Step-by-step explanation:

2 equal angles are said to be congruent

Readme [11.4K]2 years ago
4 0
Congruent angles have the same measure is answer is C

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Which expression is equivalent to (5 × 6)×(3 × 2)?
nikklg [1K]

Answer:

D

Step-by-step explanation:

it is the same exact equation, but backwards. Hope that this helps you and have a great day :)

8 0
3 years ago
Read 2 more answers
An architect increases the radius of a circle window by 20 percent. By what percent
ale4655 [162]

Answer: 44%

Step-by-step explanation:

For a circle of radius R, the area is written as:

A = pi*R^2

Where pi = 3.14

If we increase the radius by 20%, the new radius will be:

R´ = R + 0.20*R = 1.20*R

The new area will be:

A´ = pi*(1.20*R)^2 = (1.20)^2*pi*R^2

   = 1.44*pi*R^2

And pi*R^2 = A, the original area, then_

A´ = 1.44*A = A + 0.44*A

This means that the percentage in which the area increased is:

0.44*100% = 44%

6 0
2 years ago
Read 2 more answers
Real World Scenario:
iragen [17]

The distance of a train from the city depends on the speed, the time of

travel, and direction of motion of the train.

Correct responses:

  • Distance Train A is from the city: <u>750 - 75·t</u>
  • Distance Train B is from the city: 50·t
  • After <u>six</u> hours, the two trains are the same distance from the city
  • At that time both trains will be <u>300</u> miles away

1) From the time of departure of Train B to just before 6 hours after Train B's departure; 0 ≤ t < 6 hours

2) At time period, t > 6 hours

3) 250 miles

<h3>Method used to find the above response</h3>

Given:

The distance of train A from the city = 750 miles

Speed of train A = 75 mph

Time at which Train B leaves the city = When Train A is 750 miles from the city

Speed of Train B = 50 mph

Solution:

The equations are;

  • Distance of Train A from the city is; <u>x₁ = 750 - 75·t</u>
  • Distance of Train B from the city is <u>x₂ = 50·t</u>

When the train are the same distance from the city, we have;

750 - 75·t = 50·t

750 = 50·t + 75·t = 125·t

Therefore;

  • t = \mathbf{\dfrac{750}{125}} = 6

The time it takes the two trains to be the same distance from the city is 6 hours.

Which gives;

  • After <u>6</u> hours, the two trains are the same distance from the city.

The distance the trains will be after 6 hours is therefore;

750 - 75 × 6 = 300

The distance of the trains from the city after 6 hours = 300 miles

Therefore, we have;

  • At that time both trains will be <u>300</u> miles away

1) The time period Train A is further from the city is before the first 6 hours elapse; <u>0 hours ≤ t < 6 hours</u>

2) The Train B is further from the city after 6 hours of its departure from the city; <u>t > 6 hours</u>

3) The distance of Train A from the city after 4 hours is given as follows;

x₁ = 750 - 75 × 4 = 450

x₁ = 450 miles

The distance of Train B from the city after 4 hours is; x₂ = 50 × 4 = 200

x₂ = 200 miles

Therefore;

  • The distance between the trains after 4 hours = 450 miles - 200 miles = <u>250 miles</u>

Learn more about distance and time relationship equation here:

brainly.com/question/10804931

3 0
2 years ago
How much would $400 invested at 9% interest compounded continuously be worth after 3 years? Round your answer to the nearest cen
Natalka [10]
The formula to that equation:

A(t)=p *e^rt

P is the principle amount invested 400
R is the rate, 0.09 T is the 3 years.

Solve from there.
3 0
3 years ago
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Can somone help me with this please
Licemer1 [7]
The perimeter of ADC is 9.5 cm.

6 0
3 years ago
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