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kati45 [8]
3 years ago
12

Solve for x in the following system (show work) 3x+4y=8 y=3x+17

Mathematics
1 answer:
vodka [1.7K]3 years ago
7 0
3x + 4(3x+17) = 8
3x + 12x + 68 = 8
15x = - 60
x = - 4

i am a mathematics teacher. if anything to ask please pm me
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Which rule represents the translation of hexagon DEFGHI to hexagon D'E'F'G'H'I'?
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5 0
3 years ago
What is the ZERO for the graph?
Serjik [45]

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Step-by-step explanation:

5 0
3 years ago
A company manufactures light bulbs. The lifetime for these bulbs is 4,000 hours with a standard deviation of 200 hrs. What lifet
arlik [135]

Answer:

The company should promote a lifetime of 3589 hours so only 2% burnout before the claimed lifetime

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 4000, \sigma = 200

What lifetime should the company promote for these bulbs, whereby only 2% burnout before the claimed lifetime?

This is the value of X when Z has a pvalue of 0.02. So it is X when Z = -2.055.

Z = \frac{X - \mu}{\sigma}

-2.055 = \frac{X - 4000}{200}

X - 4000 = -2.055*200

X = 3589

The company should promote a lifetime of 3589 hours so only 2% burnout before the claimed lifetime

4 0
3 years ago
Joe's company sold insurance policies over the phone. Last month, 2 employees sold three hurricane policies, 6 employees sold tw
ehidna [41]

The probability that the employee sold two hurricane policies or sold one hurricane policy is 15/17.

According to the statement

Number of employees who sold three hurricane policies is 2

Number of employees who sold two hurricane policies is 6

Number of employees who sold 1 hurricane policies is 9

SO,

The total number of employees is 2+6+9=17.

The number that sold two hurricane policies or sold one hurricane policy is 6+9=15,

so the Probability = Total number of policies sold / total number of employees

Probability = 15/17

So, The probability that the employee sold two hurricane policies or sold one hurricane policy is 15/17.

Learn more about PROBABILITY here brainly.com/question/24756209

#SPJ4

8 0
2 years ago
Change 9 out of 50 to a percentage.​
Readme [11.4K]

Answer:

18%

Step-by-step explanation:

9 divided by 50

6 0
3 years ago
Read 2 more answers
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