Question

HERE IS A RECTANGLE ABCD 30CM=WIDTH AND 20CM=LENGTH AND LETTERS ABCD THE LENGH OF THE RECTANGLE IS INCREASED BY 10% AND THE WIDTH OF THE RECTANGLE I INCREASED BY 5%. WHAT IS THE PERCENTAGE INCREASE THE PERIMETER OF THE RECTANGLE?

Answer 1

Answer:

7%

Step-by-step explanation:

Perimeter of a rectangle

P = 2(w + l)

where:

• P = perimeter
• w = width
• l = length

Given:

• Width of rectangle = 30 cm
• Length of rectangle = 20 cm

Therefore, the perimeter of the original rectangle is:

⇒ P = 2(30 + 20)

⇒ P = 2(50)

⇒ P = 100 cm

If the width is increased by 5%:

⇒ new width = 30 × 1.05 = 31.5 cm

If the length is increased by 10%:

⇒ new length = 20 × 1.1 = 22 cm

Therefore, the new perimeter will be:

⇒ P = 2(31.5 + 22)

⇒ P = 2(53.5)

⇒ P = 107 cm

Percentage Increase

$\sf PI=\dfrac{final\:value-initial\:value}{initial\:value} \times 100$

Substitute the values:

$\begin{aligned} \implies \sf Percentage\:increase & = \sf \dfrac{new\:perimeter-original\:perimeter}{original\:perimeter} \times 100\\\\& = \sf \dfrac{107-100}{100} \times 100\\\\& = \sf 7\%\end{aligned}$