All categories

2 years ago

What is the value of the n in this equation n + 16 = 21

Mathematics

2 answers:

Verdich [7]2 years ago

7 0

Answer:

n = 5

Step-by-step explanation:

Given

n + 16 = 21 ( isolate n by subtracting 16 from both sides )

n = 5

Marianna [84]2 years ago

3 0

Answer:

n=5

Step-by-step explanation:

n+16=21

n=21-16

n=5

You might be interested in

For the rational expression 2x^2-7x-15/x^2-25, do both of the following,

Mrrafil [7]

Answer:

a. $\frac{2x + 3}{x+5}$

b. x ≠ -5 (Vertical asymptote) and x ≠ 5 (Hole)

Step-by-step explanation:

Factor the numerator (Grouping):

$2x^2 - 7x - 15$

Two numbers that multiply to -30 and add to -7 = -3 and 10

$[2x^2 - 10x] + [3x - 15]$

$(2x + 3)(x - 5)$

Factor the denominator (Difference of Two Squares):

$x^2 - 25$ = $(x +5)(x-5)$

Factored Expression:

(x - 5) can be factored out of top and bottom as a hole-

$\frac{(2x + 3)(x - 5)}{(x + 5)(x - 5)} = \frac{2x + 3}{x+5}$

Variable Restrictions:

Denominator ≠ 0

$x + 5 = 0\\x = -5$

Vertical asymptote at x = -5 ⇒ x ≠ -5

3 0

2 years ago

Yolanda wants to pour 91.48 grams of salt into a container so far she has poured 72.2 grams how much more salt should Yolanda po

NeTakaya

Answer:

19.28

Step-by-step explanation:

91.48 minus 72.2

5 0

2 years ago

Read 2 more answers

Solve 2x^2 + x - 4 = 0 <br> X2 +

damaskus [11]

Answer:

$\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }$

Step-by-step explanation:

Hello, please find below my work.

$2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0$

$\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}$