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seraphim [82]
3 years ago
10

4 red balls 4 white balls what is the probability of drawing at least 1 red ball if two balls are drawn

Mathematics
1 answer:
vodomira [7]3 years ago
7 0
The probability of drawing exactly one red ball is given by:
P(1\ red\ ball)=\frac{4C1\times4C1}{8C2}=\frac{16}{28}
the probability of drawing two red balls is given by:
P(2\ red\ balls)=\frac{4C2\times4C0}{8C2}=\frac{6}{28}
The probability of drawing at least one red ball is:
P(1 red ball) + P(2 red balls) = 16/28 + 6/28 = 11/14.
 The answer is \ \frac{11}{14}

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3 0
3 years ago
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Write the expresion in simplest form<br> (-11/2x+30)-2(-11/4x-5/2)
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The simplified expression of (-11/2x+30)-2(-11/4x-5/2) is 35

<h3>How to simplify the expression?</h3>

The expression is given as:

(-11/2x+30)-2(-11/4x-5/2)

Expand the bracket

-11/2x + 30 + 11/2x + 5

Collect the like terms

11/2x -11/2x + 30 + 5

Evaluate the like terms

35

Hence, the simplified expression of (-11/2x+30)-2(-11/4x-5/2) is 35

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brainly.com/question/723406

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