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seraphim [82]
3 years ago
10

4 red balls 4 white balls what is the probability of drawing at least 1 red ball if two balls are drawn

Mathematics
1 answer:
vodomira [7]3 years ago
7 0
The probability of drawing exactly one red ball is given by:
P(1\ red\ ball)=\frac{4C1\times4C1}{8C2}=\frac{16}{28}
the probability of drawing two red balls is given by:
P(2\ red\ balls)=\frac{4C2\times4C0}{8C2}=\frac{6}{28}
The probability of drawing at least one red ball is:
P(1 red ball) + P(2 red balls) = 16/28 + 6/28 = 11/14.
 The answer is \ \frac{11}{14}

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“3 less than the quotient of y and 4”
Bingel [31]

Answer:

Expression:

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2

Step-by-step explanation:

Let's take a look at the sentence:

3 less than the quotient of y and 4

3 less indicates that you will subtract

   - 3

Quotient means the result of division.

\dfrac{y}{4}

So if we combine the two, it says 3 less than the quotient so we subtract 3 from the quotient:

\dfrac{y}{4}-3

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\dfrac{y}{4}-3

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