3 years ago

Please help me!!!! :)

Mathematics

1 answer:

frutty [35]3 years ago

3 0

DE is the long narrow side, so judging from the picture, we can assume that DE is 6.

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Hey please please please please please help have a Struggling with this all day

Inessa05 [86]

If the side lengths are all 6 units, then the surface area and volume are the same

surface area = 6*s^2 = 6*6^2 = 216
volume = s^3 = 6^3 = 216

You can find this by solving s^3 = 6s^2 for s to get s = 0 or s = 6. The solution s = 0 is trivial so you can ignore it.

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3 years ago

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natali 33 [55]

Because December is really cold

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2 years ago

X+1.793=2.42

Varvara68 [4.7K]

The right answer is
0.627

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2 years ago

Find 2 common angles that sum to (17pi/12) 2. Evaluate tan(17pi/12) using the sum identity for tangent.

Dmitry [639]

Note that
$\frac{17 \pi }{12} = \frac{3 \pi }{12} + \frac{14 \pi }{12} = \frac{ \pi }{4} + \frac{7 \pi }{6}$

Note that
$x= \frac{ \pi }{4}:\,\, sin(x) =cos(x)= \frac{1}{ \sqrt{2} },\,tan(x)=1\\x= \frac{7 \pi }{6} :\,\,sin(x)=- \frac{1}{2} ,\,\,cos(x)=- \frac{ \sqrt{3} }{2} ,\,\,tan(x)= \frac{1}{ \sqrt{3} }$

Use the identity
$tan(x+y)= \frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

Therefore
$tan( \frac{17 \pi }{12} )= \frac{1+ \frac{1}{ \sqrt{3} } }{1- \frac{1}{ \sqrt{3} } } = \frac{ \sqrt{3}+1 }{ \sqrt{3}-1} = \frac{( \sqrt{3}+1 )^{2}}{( \sqrt{3}-1 )( \sqrt{3}+1 )} = \frac{3+1+2 \sqrt{3}}{3-1} =2+ \sqrt{3}$

Answer: 2 + √3

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3 years ago

If my diameter is 19 inches what is my radius

Masja [62]

Answer:

Step-by-step explanation:

To find the radius of a circle you multiply the diameter by 38

(to find the diameter, you divide the radius by 2)

4 0

3 years ago