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gavmur [86]
3 years ago
5

Todd’s average score for six tests was 92. If the sum of the scores of two of her tests was 188, then what was her average score

for the other four tests? Show all work
Mathematics
2 answers:
asambeis [7]3 years ago
6 0

Answer:

91

Step-by-step explanation:

Sum of 6 tests:

6 × 92 = 552

Sum of 2 tests: 188

Sum of 4 tests:

552 - 188 = 364

Average of these 4 tests:

364/4

91

natita [175]3 years ago
3 0

Answer:

91

Step-by-step explanation:

Todd’s average score for six tests = 92.

The sum of two of her test = 188

First, we need to find the total score for the six test. This given below:

Average = sum of all test / number of test

sum of all the test = average x number of test

average score for six tests = 92.

Number of test = 6

Sum of all the Tests = 92 x 6 = 552

Sum of four test = sum of all the test — sum of two test

Sum of four test = 552 — 188 = 364

Now we can solve for the average of the other four test as shown below:

Average of four test = 364/4= 91

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Answer:

x = 2\sqrt{66}

Step-by-step explanation:

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marusya05 [52]

Answer:

D=2.82

Step-by-step explanation:

Here we are given with two coordinates and asked to determine the distance between them.

Here we are going to use the distance formula, which is given as under

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Where

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Replacing these values in the distance formula

D =\sqrt{(-1-(-3))^2+(2-4)^2}

D =\sqrt{(-1+3)^2+(-2)^2}

D =\sqrt{(2)^2+4}

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Hence the Distance is 2.82 units

3 0
3 years ago
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I need the answer for this
Svetach [21]

Answer:

535.9 ft²

Step-by-step explanation:

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iren [92.7K]

Answer:

4 miles.

Step-by-step explanation:

3.50 ×4=11.50.

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Read 2 more answers
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