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zimovet [89]
2 years ago
11

which metod is most efficent in solving a system of linear equations when the two equations have x-values with opposite coeffici

ent values?
Mathematics
1 answer:
telo118 [61]2 years ago
3 0

Answer:

See below

Step-by-step explanation:

Just add the two equations together....this will eliminate 'x' and you can then solve for 'y'

  Use this value of 'y' in one of the equations to calculate the value of 'x'

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What is six less than seven times a number is equal to -20​
Naya [18.7K]

Answer:

7n-6=-20

Step-by-step explanation:

six less than seven times a number

we'll use n as "the number"

six less meaning -6

7 times a number n = 7n

7n-6=-20

7 0
3 years ago
Anyone want to ch at?
algol13

Answer:

sure?

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
I need help answering this question, Asap
Natasha2012 [34]

Answer:

(-65)/17

Step-by-step explanation:

Evaluate 3/(x - 2) - sqrt(x - 3) where x = 19:

3/(x - 2) - sqrt(x - 3) = 3/(19 - 2) - sqrt(19 - 3)

19 - 3 = 16:

3/(19 - 2) - sqrt(16)

19 - 2 = 17:

3/17 - sqrt(16)

sqrt(16) = sqrt(2^4) = 2^2:

3/17 - 2^2

2^2 = 4:

3/17 - 4

Put 3/17 - 4 over the common denominator 17. 3/17 - 4 = 3/17 + (17 (-4))/17:

3/17 - (4×17)/17

17 (-4) = -68:

3/17 + (-68)/17

3/17 - 68/17 = (3 - 68)/17:

(3 - 68)/17

3 - 68 = -65:

Answer: (-65)/17

4 0
3 years ago
Read 2 more answers
A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on
SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

Z_{1-\alpha /2}= Z_{0.95}= 1.645

[10.41±1.645*(\frac{3.71}{\sqrt{28} } )]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0
3 years ago
Rearrange the equation so w is the independent variable.<br> u-5=-4(w-1)
exis [7]

u-5=-4(w-1) \\u=5-4(w-1)\\u=5-4w+4\\u=-4w+9

5 0
3 years ago
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