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3 years ago

11

which metod is most efficent in solving a system of linear equations when the two equations have x-values with opposite coeffici

ent values?

1 answer:

telo118 [61]3 years ago

3 0

Answer:

See below

Step-by-step explanation:

Just add the two equations together....this will eliminate 'x' and you can then solve for 'y'

Use this value of 'y' in one of the equations to calculate the value of 'x'

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Two trains started moving at the same time, train A from Boston to New York, and train B from New York to Boston. The distance b

elena55 [62]

Answer:

2 hours

Step-by-step explanation:

Train B's speed: 4/3 × 60 = 80

Combined speed = 80 + 60 = 120

Time = 240/120 = 2

8 0

4 years ago

Tickets to a baseball game cost $12 for adults and $7 for children. How much will tickets cost for 3 adults and 4 children?

ludmilkaskok [199]

Answer:

So total cost of tickets = $64

Step-by-step explanation:

Given:

Cost of adult = $12

Cost of Children = $7

Total Adults = 3

Total children = 4

To Find:

Total Cost = ?

Solution:

We are given per person price and no of persons too now

Total cost = Cost of children ticket + Cost of Adults ticket

Now we will find the values

Cost of 3 adults ticket = total person * cost per person

= 3 * 12

=$36

Cost of 4 Children ticket = total person * cost per person

= 4 * 7

=$28

Now

Total cost = Cost of children ticket + Cost of Adults ticket

putting value

Total cost = 28 + 36

= $ 64

So total cost of tickets = $64

4 0

4 years ago

How many days are in a month

ser-zykov [4K]

It could be 30 to 31 but February has 28 expected from a leap year with 29 days

7 0

3 years ago

Read 2 more answers

What is the value of a?

emmasim [6.3K]

Answer:

A=8

Step-by-step explanation:

If you use the formula 30-60-90 which is a-radical 3a-2a

since the hypotenuse is 2a it equals 16

therefore if its 2a all you need to do is divide it where then you get 8.

6 0

3 years ago

Write the partial fraction decomposition fro the ration expression below

zlopas [31]

$\dfrac{5x-2}{(x-1)^2}=\dfrac a{x-1}+\dfrac b{(x-1)^2}$
$5x-2=a(x-1)+b$

Since $5x-2=5x-5+3=5(x-1)+3$ , it follows that $a=5$ and $b=3$ , so

$\dfrac{5x-2}{(x-1)^2}=\dfrac5{x-1}+\dfrac3{(x-1)^2}$

$\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac{x^3+x+x+2}{x^2(x^2+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac{cx+d}{x^2+1}$
$x^3+x^2+x+2=ax(x^2+1)+b(x^2+1)+(cx+d)x^2$
$x^3+x^2+x+2=(a+c)x^3+(b+d)x^2+ax+b$

When $x=0$ , you find that $b=2$ . It's also clear that $a=1$ . So the remaining constants must be $1+c=1\implies c=0$ and $2+d=1\implies d=-1$ , and so you get

$\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac1x+\dfrac2{x^2}-\dfrac1{x^2+1}$

6 0

4 years ago