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NISA [10]
4 years ago
14

Triangle ABC has been dilated to form triangle A'B'C'. If sides AB and A'B' are proportional, what is the least amount of additi

onal information needed to determine if the two triangles are similar? Angles B and B' are congruent, and angles C and C' are congruent. Segments AC and A'C' are congruent, and segments BC and B'C' are congruent. Angle C=C', angle B=B', and segments BC and B'C' are congruent. Segment BC=B'C', segment AC=A'C', and angles B and B' are congruent.
Mathematics
2 answers:
snow_tiger [21]4 years ago
4 0

Answer:

Its Angles B and B' are congruent, and angles C and C' are congruent.

Ede4ka [16]4 years ago
3 0
When considering similar triangles, we need congruent angles and proportional sides.

Hence
"Angles B and B' are congruent, and angles C and C' are congruent." is sufficient to prove similarity of two triangles.

"Segments AC and A'C' are congruent, and segments BC and B'C' are congruent." does not prove anything because we know nothing about the angles.

"Angle C=C', angle B=B', and segments BC and B'C' are congruent." would prove ABC is congruent to A'B'C' if and only if AB is congruent to A'B' (not just proportional).

"<span>Segment BC=B'C', segment AC=A'C', and angles B and B' are congruent</span>" is not sufficient to prove similarity nor congruence because SSA is not generally sufficient.

To conclude, the first option is sufficient to prove similarity (AAA)

You might be interested in
If a polynomial function f(x) has roots 3+root5 and -6, what must be a factor of f(x)? (X+(3-root5) (x-(3-root5)) (x+(5+root3))
belka [17]

Answer:

(x-(3+\sqrt5)) or (x-3-\sqrt5) is a factor of the given polynomial.

Step-by-step explanation:

Let us learn the concept with an example first.

Let the polynomial be a quadratic function g(x).

g(x) = x^{2} -5x+6

The roots of g(x) are 2 and 3.

Putting x= 2\ in \ g(x)

2^2-5\times 2+6 = 4-10+6 =0

Putting x= 3\ in \ g(x)

3^2-5\times 3+6 = 9-15+6 =0

Putting x = 2 or x = 3, g(x) = 0 \therefore The roots of equation g(x) are 2 and 3.

Now, let us try to factorize g(x):

x^{2} -2x-3x+6\\\Rightarrow x(x -2)-3(x-2)\\\Rightarrow (x-3)(x-2)

so, the equation can be written as:

g(x) = x^{2} -5x+6=(x-3)(x-2) where 3 and 2 are the roots of equation.

The factors are (x-3) and (x-2).

\therefore for the polynomial f(x) which has roots 3+\sqrt5\ and\ -6 will have a factor:

(x-(3+\sqrt5)) or (x-3-\sqrt5)

8 0
4 years ago
If the second term of a geometric sequence of real numbers is -2 and the fifth term is 16 then what is the fourteenth term?
Agata [3.3K]
<h3>Given</h3>

A geometric sequence such that ...

a_2=-2\quad\text{and}\quad a_5=16

<h3>Find</h3>

a_{14}

<h3>Solution</h3>

We can use the ratio of the given terms to find the common ratio of the sequence, then use that to find the desired term from one of the given terms. We don't actually need the common ratio (-2). All we need is its cube (-8).

a_2=a_1r^{(2-1)}=a_1r^1\\a_5=a_1r^{(5-1)}=a_1r^4\\a_{14}=a_1r^{(14-1)}=a_1r^13=a_5r^9\\\\\dfrac{a_5}{a_2}=\dfrac{a_1r^4}{a_1r^1}=r^3=\dfrac{16}{-2}=-8\\\\r^9=\left(r^3\right)^3=(-8)^3=-512\\a_{14}=a_5(-512)\\\\a_{14}=-8192

7 0
3 years ago
What is 9 ^ 5? Need this fast!!!
Zielflug [23.3K]
9^5 is 45
As, 9+9+9+9+9 =45
5 0
3 years ago
Which is the area of the rectangle?
Zigmanuir [339]
The answer is a the length is 69 and the base is 115 and if you multiply 115*69 you will get 7935 square units
6 0
3 years ago
Answer these Questions for me pleaseeeee....
Thepotemich [5.8K]

Answer:

A. 31

B. 5

C. 9/31 or 0.29%

D. 2/31 or 0.06%

E. 0 or unknown

Step-by-step explanation:

A is the addition of all the entries, B is the number of entries that said snakes, C and D are about how many out of the total can give you the corresponding animal, chances are always part/total so for C it's 9/31 and D is 2/31. E is 0 or unknown because there is no "Frog" entries as favorite pet so it must be either 0 or unknown because you don't get the information

<em>pls brainliest if you found useful</em>

3 0
3 years ago
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