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NISA [10]
3 years ago
14

Triangle ABC has been dilated to form triangle A'B'C'. If sides AB and A'B' are proportional, what is the least amount of additi

onal information needed to determine if the two triangles are similar? Angles B and B' are congruent, and angles C and C' are congruent. Segments AC and A'C' are congruent, and segments BC and B'C' are congruent. Angle C=C', angle B=B', and segments BC and B'C' are congruent. Segment BC=B'C', segment AC=A'C', and angles B and B' are congruent.
Mathematics
2 answers:
snow_tiger [21]3 years ago
4 0

Answer:

Its Angles B and B' are congruent, and angles C and C' are congruent.

Ede4ka [16]3 years ago
3 0
When considering similar triangles, we need congruent angles and proportional sides.

Hence
"Angles B and B' are congruent, and angles C and C' are congruent." is sufficient to prove similarity of two triangles.

"Segments AC and A'C' are congruent, and segments BC and B'C' are congruent." does not prove anything because we know nothing about the angles.

"Angle C=C', angle B=B', and segments BC and B'C' are congruent." would prove ABC is congruent to A'B'C' if and only if AB is congruent to A'B' (not just proportional).

"<span>Segment BC=B'C', segment AC=A'C', and angles B and B' are congruent</span>" is not sufficient to prove similarity nor congruence because SSA is not generally sufficient.

To conclude, the first option is sufficient to prove similarity (AAA)

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kenny6666 [7]

Answer:

6y - 3y - 7 = -2 +3

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3y -7 = 1

Add 7 to both sides:

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Divide both sides by 3:

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There is only one solution.

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If tan theta = startfraction 11 over 60 endfraction, what is the value of cot theta?
Dennis_Churaev [7]

The value of cot\theta when tan\theta =\frac{11}{60} comes to be \frac{60}{11}.

Given that trigonometric ratio:

tan\theta = \frac{11}{60}

<h3>What is the tangent of an angle?</h3>

The tangent of an angle is the ratio of the opposite side(to that angle) to the adjacent side(to that angle).

So, for the given problem

Opposite side to \theta = 11

Adjacent side to \theta = 60

So, cot \theta =\frac{AdjacentSide }{OppositeSide}

cot\theta =\frac{60}{11}

Therefore, the value of cot\theta when tan\theta =\frac{11}{60} comes to be \frac{60}{11}.

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6 0
2 years ago
Please help with 1 , and 2 I really don’t understand this!
elena-s [515]
1. B
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hope this helped
6 0
2 years ago
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Answer:

x+2

Step-by-step explanation:

\frac{x ^{2} + 4x + 4 }{x + 2}  \\ \frac{(x) ^{2} + 2 \times x \times 2 + (2) ^{2}  }{x + 2}  \\ \   \frac{(x + 2) ^{2} }{x + 2}  \\  \frac{(x + 2)(x + 2)}{x + 2}  \\ x + 2

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