Answer:
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Begin with the right hand side:
R.H.S = cot θ =
L.H.S = sin θ cos θ
so, sin θ cos θ ≠ 
So, the equation is not a trigonometric identity.
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<u>Anther solution:</u>
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Assume θ with a value and substitute with it.
Let θ = 45°
So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2
R.H.S = cot θ = cot 45 = 1
So, L.H.S ≠ R.H.S
So, sin θ cos θ = cot θ is not a trigonometric identity.
Answer:
<h2>Center: (3, 0)</h2><h2>Radius: 2√2</h2>
Step-by-step explanation:
The equation of a circle in standard form:

(h, k) - center
r - radius
We have the equation:

Therefore
the center: 
the radius: 
Answer: (3, 4)
Step-by-step explanation:
i graphed both of them and found the solution <33
Answer:
a = -1
Step-by-step explanation:
The line of symmetry for the parabola given by ...
y = ax² +bx +c
is
x = -b/(2a)
Using the given values, we have ...
-2 = -(-4)/(2a)
Multiplying by -a/2, we get ...
a = (4/2)(-1/2) = -1
The value of "a" is -1.