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algol [13]
3 years ago
14

M <ABE=(7x+28)°And m <DBC=(9x-2)°. Find the measure of <ABE

Mathematics
1 answer:
Ugo [173]3 years ago
5 0
Are the angles congruent? If so the the answer is 133 degrees
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prove that sin theta cos theta = cot theta is not a trigonometric identity by producing a counterexample
Zolol [24]

Answer:

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Begin with the right hand side:

R.H.S = cot θ = \frac{cos \ \theta}{sin \ \theta}

L.H.S = sin θ cos θ

so, sin θ cos θ ≠ \frac{cos \ \theta}{sin \ \theta}

So, the equation is not a trigonometric identity.

=========================================================

<u>Anther solution:</u>

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Assume θ with a value and substitute with it.

Let θ = 45°

So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2

R.H.S = cot θ = cot 45 = 1

So, L.H.S ≠ R.H.S

So, sin θ cos θ = cot θ is not a trigonometric identity.

5 0
3 years ago
Find center and radius<br> (x-3)^2+y^2=8
Flauer [41]

Answer:

<h2>Center: (3, 0)</h2><h2>Radius: 2√2</h2>

Step-by-step explanation:

The equation of a circle in standard form:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the equation:

(x-3)^2+y^2=8\to(x-3)^2+(y-0)^2=(\sqrt8)^2

Therefore

the center: (3,\ 0)

the radius: r=\sqrt8\to r=\sqrt{4\cdot2}\to r=\sqrt4\cdot\sqrt2\to r=2\sqrt2

4 0
3 years ago
Context inequality systems on
MariettaO [177]
Yea I don’t know it’s b
8 0
3 years ago
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Solve the following system of equations graphically.
liraira [26]

Answer: (3, 4)

Step-by-step explanation:

i graphed both of them and found the solution <33

3 0
3 years ago
Read 2 more answers
Hello!! I Need HElp ASAP PLEAASSEE
MatroZZZ [7]

Answer:

  a = -1

Step-by-step explanation:

The line of symmetry for the parabola given by ...

  y = ax² +bx +c

is

  x = -b/(2a)

Using the given values, we have ...

  -2 = -(-4)/(2a)

Multiplying by -a/2, we get ...

  a = (4/2)(-1/2) = -1

The value of "a" is -1.

8 0
3 years ago
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