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2 years ago

how much will you save if you buy an item listed at 17.50 at a 35 percent discount? savings = price x discount percentage

Mathematics

2 answers:

kenny6666 [7]2 years ago

7 0

Answer:

17.50 × 0.35 = 6.13

Step-by-step explanation:

hodyreva [135]2 years ago

5 0

Answer:

That would be $11.37

Step-by-step explanation:

First Multiply the discount and the original price

17.50(0.35)= 6.125 = 6.13

Use that answer and subtract it from the original price

17.50 - 6.13 = 11.37

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The average demand for rental skis on winter Saturdays at a particular area is 150 pairs, which has been quite stable over time.

pentagon [3]

Answer:

a) 15.87% probability that demand will exceed this supply on any winter Saturday

b) The shop needs to have 197 pairs of skis in stock.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 150, \sigma = 20$

(a) The rental shop stocks 170 pairs of skis. What is the probability that demand will exceed this supply on any winter Saturday?

This probability is 1 subtracted by the pvalue of Z when X = 150. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{170 - 150}{20}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

1 - 0.8413 = 0.1587

15.87% probability that demand will exceed this supply on any winter Saturday

(b) How many pairs of skis in stock does the shop have to have to make the probability in question (a) less than .01?

This is X when Z has a pvalue of 0.99.

So X when Z = 2.33

$Z = \frac{X - \mu}{\sigma}$

$2.33 = \frac{X - 150}{20}$

$X - 150 = 2.33*20$

$X = 196.6$

Rounding up, since the number of pairs is a discrete number

The shop needs to have 197 pairs of skis in stock.

6 0

3 years ago

A stock has had returns of 11 percent, 18 percent, 20 percent, −13 percent, 25 percent, and −9 percent over the last six years.

Naily [24]

Answer: a) 8.67%, b) 7.64%.

Step-by-step explanation:

Since we have given that

Stock has returns is given by

11 percent, 18 percent, 20 percent, −13 percent, 25 percent, and −9 percent

Number of years = 6

Arithmetic average returns for the stock is given by

$\dfrac{11+18+20-13+25-9}{6}\\\\=8.67\%$

Geometric average returns for the stock is given by

$[(1+0.11)\times (1+0.18)\times (1+0.20)\times (1-0.13)\times (1+0.25)\times (1-0.09)]^{\frac{1}{6}}-1\\\\=[1.11\times 1.18\times 1.20\times 0.87\times 1.25\times 0.91]^{\frac{1}{6}}-1\\\\=7.64\%$

Hence, a) 8.67%, b) 7.64%.

6 0

3 years ago

Nance is riding her bike to a friend’s house 4 and 1/2 miles away. She’s ridden 2 and 3/5 miles. How much farther does she need

Alinara [238K]

<h2>Hello!</h2>

The answer is:

She still needs to ride

$1\frac{9}{10}miles$

From the statement, we know that Nance's friend is 4 1/2 miles away and she only has ridden 2 3/5 miles.

So, let be "x" the distance that she still need to ride to get to her friend's house.

The equation will be:

$TotalDistance=RiddenDistance+x$

Remember that:

$a\frac{b}{c}=a+\frac{b}{c}$

Also, if we need to add/substract fractions we must remember that:

$\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}$

If we need to switch fractions to mixed numbers, we need to:

- Perform the division

- Keep the whole number and make a fraction with the aproximated next whole number (remainder) as numerator, and the original denominator. We need to use the remainder to approximate to the next whole number.

$\frac{a}{b}=c.r$

Where:

$a=numerator\\b=denominator\\c=WholePart\\r=NextWholeNumber$

So,

$\frac{a}{b}=c\frac{r}{b}$

Then, substituting the given information into the equation, we have:

$4\frac{1}{2} =2\frac{3}{5} +x\\\\x=(4\frac{1}{2}) -(2\frac{3}{5})=4+\frac{1}{2}-2-\frac{3}{5}=2+\frac{1}{2}-\frac{3}{5}\\\\x=2+\frac{1}{2}-\frac{3}{5}=2+\frac{5-6}{10}=2-\frac{1}{10}\\\\x=2-\frac{1}{10}=\frac{20-1}{10}=\frac{19}{10}$