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3 years ago

PLEASE HELP!!!! MATCH THE ANSWERS!! WILL GIVE BRAIN PLEASE!!!!

Mathematics

2 answers:

Oksanka [162]3 years ago

7 0

Answer:

Range - a is y<k

Range + a is y>k

Doman always all real numbers

Step-by-step explanation:

mr Goodwill [35]3 years ago

7 0

Answer:

domain- always all real numbers

and im not too certain about the last 2 but im pretty sure that

range-a is less than or equal to whereas range+a is more than or equal to.

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The diagram shows a circle inside a square. work out the area of the circle

Alona [7]

Answer:

i don't know the answer as you haven't given the diagram

Step-by-step explanation:

asumming the circle is touching the square the length of the sides of the square is the diameter of the circle using this information you use the formula area= pie*radius squared find the area.

(radius=half the diameter0

7 0

2 years ago

I’m completely lost can anybody help solve this

Marizza181 [45]

Answer:

$\huge\boxed{x=54^o}$

Step-by-step explanation:

Look at the picture.

We have:

$l=108^o$

Therefore

$2\alpha=108^o$ divide both sides by 2

$\dfrac{2\alpha}{2}=\dfrac{108^o}{2}\\\\\alpha=54^o$

7 0

3 years ago

Geometry helppp please ;c

nignag [31]

What’s the question?

4 0

3 years ago

Read 2 more answers

9x + 3 – 7x + 4 Help me out please?

SOVA2 [1]

Answer: The answer is 2x + 7.

Explanation: First, we need to add the numbers:

9x + 3 – 7x + 4

9x + 7 - 7x

And finally, we combine like terms:

9x + 7 - 7x

2x + 7

8 0

2 years ago

Read 2 more answers

Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into

Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = $(\frac{60\pi }{\pi+4}) in$

b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

b= $\frac{y}{4}$

Area of the square which is L² can now be said to be;

$A_S=(\frac{y}{4})^2 = \frac{y^2}{16}$

On the otherhand; let the radius (r) of the circle be;

2πr = 60-y

$r = \frac{60-y}{2\pi }$

Area of the circle which is πr² can now be;

$A_C= \pi (\frac{60-y}{2\pi } )^2$

$=( \frac{60-y}{4\pi } )^2$

Total Area (A);

A = $A_S+A_C$

= $\frac{y^2}{16} +(\frac{60-y}{4\pi } )^2$

For the smallest possible area; $\frac{dA}{dy}=0$

∴ $\frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0$

If we divide through with (2) and each entity move to the opposite side; we have:

$\frac{y}{18}=\frac{(60-y)}{2\pi}$

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

$y= \frac{240}{\pi+4}$

∴ since $y= \frac{240}{\pi+4}$ , we can determine for the length of the circle ;

60-y can now be;

= $60-\frac{240}{\pi+4}$

= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

also, the length of wire for the square (y) ; $y= (\frac{240}{\pi+4})in$

The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0

3 years ago