Say the width is W and the length is L
L=3W (and of course W=W)
Now you use the perimeter formula P=2L+2W
80=2(3W) + 2W)
80=6W+2W
80=8W Divide both sides by 8
W=10
Now that you know the width, substitute it back into L=3W to find the length
L=3(10)
L=30
The dimensions are length: 30 cm and width: 10 cm
Answer:
a)
,
, b)
,
, c)
,
.
Step-by-step explanation:
The equation of the circle is:

After some algebraic and trigonometric handling:


Where:


Finally,


a)
,
.
b)
,
.
c)
, 
Where:


The solution is 
The parametric equations are:


2x-4=3-x +1
<span>Simplifying
2x + -4 = 3 + -1x + 1
Reorder the terms:
-4 + 2x = 3 + -1x + 1
Reorder the terms:
-4 + 2x = 3 + 1 + -1x
Combine like terms: 3 + 1 = 4
-4 + 2x = 4 + -1x
Solving
-4 + 2x = 4 + -1x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add 'x' to each side of the equation.
-4 + 2x + x = 4 + -1x + x
Combine like terms: 2x + x = 3x
-4 + 3x = 4 + -1x + x
Combine like terms: -1x + x = 0
-4 + 3x = 4 + 0
-4 + 3x = 4
Add '4' to each side of the equation.
-4 + 4 + 3x = 4 + 4
Combine like terms: -4 + 4 = 0
0 + 3x = 4 + 4
3x = 4 + 4
Combine like terms: 4 + 4 = 8
3x = 8
Divide each side by '3'.
x = 2.666666667
Simplifying
x = 2.666666667</span>
Answer:
the probability that the shipment is accepted is 0.8865
Step-by-step explanation:
Given the data in the question;
N = 86, n/d = 5 and n = 2
now, without replacement
the probability that the shipment is accepted will be;
probability that the shipment is accepted = probability that non is defectives
so p( non is defective ) = ( (86-5)/86) × ((86-5-1)/(86-1))
p( non is defective ) = ( 81 / 86) × (80/85)
p( non is defective ) = 0.8865
Therefore, the probability that the shipment is accepted is 0.8865