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LekaFEV [45]
2 years ago
15

Find the value of y in the solution to the system of equations shown.

Mathematics
2 answers:
zlopas [31]2 years ago
8 0
  • 3y=18x+6

Divide by 3

  • y=6x+2--(1)
  • y=2x+14--(2)

Equating

  • 6x+2=2x+14
  • 4x=12
  • x=3

Now

  • y=6(3)+2
  • y=18+2
  • y=20

C

Kryger [21]2 years ago
6 0

Answer:

C.  y = 20

Step-by-step explanation:

Given system of equations:

\begin{cases}3y = 18x + 6\\y = 2x + 14\end{cases}

Multiply the second equation by 3:

\implies (3)y=(3)2x+(3)14

\implies 3y=6x+42

Subtract this from the first equation to eliminate 3y:

\begin{array}{r l}3y & = 18x+6\\-\quad3y&=6x+42\\\cline{1-2}0&=12x-36\end{array}

Solve the resulting equation for x:

\implies 12x-36=0

\implies 12x=36

\implies x=3

Substitute the found value of x into the original second equation and solve for y:

\implies y=2(3)+14

\implies y=6+14

\implies y=20

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Step-by-step explanation:

The domain is the set of all x values in the function. The range is the set of all y values in the function. It is written in parenthesis from least to greatest. Do not repeat values even if the function has them more than once.

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Dimes (.10): y


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Quantity:        x  +    y  = 60   →       1(x  +    y  = 60)           →   <u> x  + y </u> = <u> 60 </u>

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Next, substitute "29" for "y" into either equation and solve for "x":

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