in the diagram, the length of S is 2/3 the length of T. If S has an area of 368 cm squared, find the perimeter of the figure.
1 answer:
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Answer:
0.44ft/hr
Step-by-step explanation:
Given parameters:
Quantity of rainfall = 8inches
1ft = 12inches
so;
= 0.67ft
Time = hr
Unknown:
Rate of rainfall expressed in ft/hr = ?
Solution:
The rate of the rainfall is given as;
Rate =
Rate = = 0.44ft/hr
Answer:
The height of the tree=8.42 m
Step-by-step explanation:
We are given that
Height of Joshua, h=1.45 m
Length of tree's shadow, L=31.65 m
Distance between tree and Joshua=26.2 m
We have to find the height of the tree.
BC=26.2 m
BD=31.65m
CD=BD-BC
CD=31.65-26.2=5.45 m
EC=1.45 m
All right triangles are similar .When two triangles are similar then the ratio of their corresponding sides are equal.
Substitute the values
Hence, the height of the tree=8.42 m
