Applying the distributive property, we would simplify the expression as: 5f + 16f = (5 + 16)f = 21f.
<h3>How to Apply the Distributive Property?</h3>
The distributive property states that, ab + ac = (b + c)a.
Using the distributive property, we have:
5f + 16f
= (5 + 16)f
= 21f
Therefore, 5f + 16f is simplified as 21f.
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1/5 because it’d be 2/10 , 2/10 simplified is 1/5
I put it them on a graph, they look like a straight line to me. That makes it Linear!
Answer:
False
Any integers that the numbers 5, 10 , 15 but 20 can be used as a counter argument against the statement.
Step-by-step explanation:
The claim is that A⊆B which stands for that A is a SUBSET in B, or that B contains A.
The truth is that B⊆A since 5 has more possible outcomes than 20 in the number of integers.
So the list of all possible answers are r5, r10, and r15 where N⊆Z.
For example I choose r=3 and r15, 3(15)= 45. I can use the number 45 as a counter argument that the statement of A⊆B is false.
