All categories

3 years ago

Coefficient of x^2(px^2+4x+r)×(4x^2-3qx-5)

Mathematics

1 answer:

tankabanditka [31]3 years ago

4 0

Step-by-step explanation:

left side of the expression has an x^2 term, x term and constant(x^0 term), same for the right side of the expression

x^2 coefficient = p(-5) + 4(-3qx) = -5p -12qx

You might be interested in

PLEASE HELP! GIVING AWAY 20 POINTS TO BRAINLIEST ANSWER!

murzikaleks [220]

25/200 i AM SURE IT IS THIS ANSWER sorry caps lock
Hope this helps

3 0

3 years ago

Read 2 more answers

The diameter of a circle is 3 ft. Find the circumference to the nearest tenth.

Tom [10]

To find radius
Diameter divided by 2 = radius
So it’s 1.5
To find circumference
C=2pi*radius
So 2pi*1.5=9.42

4 0

3 years ago

Read 2 more answers

Write an expression for the sequence of operations described below.

Aleks [24]

Answer:

g/(2 x 3)

Step-by-step explanation:

Your expression will be:

-Double 3 = multiply 3 by 2

-Divide g by the result (2 × 3)

g/(2 × 3)

6 0

3 years ago

Read 2 more answers

From the number 0,1,2,3,4,5

lubasha [3.4K]

Answer:

25, 432, 120

Step-by-step explanation:

a. 5 × 5 = 25 ways

b. 2 × 6 × 6 × 6 = 432 ways

c. 2 × 5 × 4 × 3 = 120 ways

4 0

3 years ago

Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx

shutvik [7]

$\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)$

Let $v=x+y$ , so that $\dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}$ :

$\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1$

Now the ODE is separable, and we have

$\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx$

For the integral on the left, rewrite the integrand as

$\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v$

Then

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C$

and so

$\csc v-\cot v=x+C$

$\csc(x+y)-\cot(x+y)=x+C$

Given that $y(0)=\dfrac\pi2$ , we find

$\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1$

so that the particular solution to this IVP is

$\csc(x+y)-\cot(x+y)=x+1$

5 0

3 years ago

Coefficient of x^2(px^2+4x+r)×(4x^2-3qx-5)​

Coefficient of x^2(px^2+4x+r)×(4x^2-3qx-5)