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2 years ago

Any help? question in the photo.

Biology

1 answer:

BartSMP [9]2 years ago

5 0

Answer:

The lymphatic system is a combination of circurlatory and immune systems

Explanation:

yw :))

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What does the model suggest about a mechanism for regulating ph in an organism?

Goryan [66]

The answer is c02 regulation, the carbonic acid bicarbonate buffer regulation, the H+ regulation and gas exchange. The following regulations are all completed through the circulatory, excretory and respiratory systems which is part of one huge function that is called homeostasis. Homeostasis is the predisposition to repel alteration in order to uphold a even comparatively constant internal situation.

7 0

3 years ago

Which organisms are most closely related? remember, the name of an organism is in the form genus species.

Crazy boy [7]

B because they share the same genus.

8 0

4 years ago

Read 2 more answers

The relationship between heredity and environment is

Lilit [14]

Not the same and they is not in a relationship

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4 years ago

Fresh raspberry contains 80% water. dried raspberry contains only 20% water. what weight of dried raspberry can you get from 36

adell [148]

There 2 ways to solve this

1- Directly :

80% of water in the fresh berries è 20% of water in the dried berries

36 Ibs of the fresh berries è X Ibs of the dried berries

X = $\frac{36 * 20}{80}$ = 9 Ibs

2- If you do not understand the first method, the second one is more explicit:

First, we gonna calculate the weight of the berries without water (dehydrated):

36 * 80% = 28.8 Ibs (of water in the berries)

Then:

36 – 28.8 = 7.2 Ibs (of completely dehydrated berries)

Next, we gonna add 20% of water in the dehydrated berries:

X (total weight of dried berries) è 100%

7.2 Ibs of dehydrated berries è 80%

X = $\frac{7.2 * 100}{80}$ = 9 Ibs

4 0

3 years ago

How many possible open reading frames (frames without stop codons) are there that extend through the following sequence? 5'... C

fenix001 [56]

Answer:

There are 4 reading frames without stop codons.

Explanation:

1) To find the possible reading frames you need to separate your sequence in codons (trios) for the 5'-> 3' sense, first, excluding the first nucleotide, then excluding 2 nucleotides and then not excluding nucleotides.

5'... C TTA CAG TTT ATT GAT ACG GAG AAG G... 3' NO STOP CODON

5'... CT TAC AGT TTA TTG ATA CGG AGA AGG... 3' NO STOP CODON

5'... CTT ACA GTT TAT TGA TAC GGA GAA GG... 3'

2)Then you find the complementary sequence (which you already have)

3'... GAA TGT CAA ATA ACT ATG CCT CTT CC... 5'

3'... GA ATG TCA AAT AAC TAT GCC TCT TCC... 5'

3'... G AAT GTC AAA TAA CTA TGC CTC TTC C... 5'

3) Next, you have to obtain the reverse complementary

CCT TCT CCG TAT CAA TAA ACT GTA AG NO STOP CODON

CC TTC TCC GTA TCA ATA AAC TGT AAG NO STOP CODON

C CTT CTC CGT ATC AAT AAA CTG TAA G

4)Now you need to find start (AGT in terms of DNA) and stop codons(TAA, TAG, TGA, also in terms of DNA), in 5->3 and de reverse complementary.

As you can see, you have for open reading frames that lack of stop codon, unfortunately, they also lack of AGT, the start codon.

I added a table where you can find thestart and stop codons as well as the proteins that they translate to in terms of RNA.

I hope you find this information interesting and useful, good luck!

8 0

3 years ago