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2 years ago

Will a stand that can hold up to 40 pounds support a21-kilograms television? Explain. Use 2.2 lb=1kg.

Mathematics

1 answer:

svet-max [94.6K]2 years ago

7 0

Answer: No

Step-by-step explanation:

Weight limit = 40 Lb

Weight given = 21 kg

Conversion factor

2.2 Lb = 1 kg

2.2 x 21 = 46.2

46.2 Lb = 21 kg

46.2 > 40, the stand cannot support the TV

TV > stand

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Houa is ordering a taxi from an online taxi service. The taxi charges $3.50 just for the pickup and then an additional $1.25 per

statuscvo [17]

Answer:

<u>Cost for 6 Miles:</u> 7.50$

<u>Cost in General:</u> 11$

Step-by-step explanation:

1.25x6=7.50

7.50+3.50=11

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2 years ago

Please help me with this question!! :)

Gre4nikov [31]

Answer:

D. The last 26/8, 3-32, -Pi, -4 2/3

Step-by-step explanation:

26/8= 3.25

3-32=3.17

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6 months ago

A cable television compan is laying cable in an area with underground utilities. Two subdivisions are located on opposite sides

Schach [20]

Answer:

Step-by-step explanation:

Given:

Point Q = Q is on the north bank 1200 m east of P $40/m to lay cable underground and $80/m way to lay the cable.

Lets denote T be a point on north bank, therefore, point T is t m east and 100m north of P.

Note that 0 < t < 1200

Distance from P to T using Pythagoras theorem:

PT^2 = PQ^2 + QT^2

PT = √(t²+100²) = √(t²+10,000)

Distance from T to Q:

TQ = 1200 - t

From above, Cable from P to T is underwater, and costs $80/m to lay.

Cable from T to Q is underground, and costs $40/m to lay.

Total cost of the cable:

C(t) = 80√(t²+10,000) + 40(1200 - t)

Cost is at its minimum: when dC/dt = C'(t) = 0 and d^2C/dt^2 = C''(t) > 0

dC/dt = C'(t)

= 80 * 1/2 (t² + 10,000)^(-1/2) × 2t + 40 × (-1)

dC/dt = C'(t)

= 80t/√(t² + 10,000) - 40 = 0

80t/√(t² + 10,000) = 40

80t = 40√(t² + 10,000)

2t = √(t² + 10,000)

square both sides:

4t² = t² + 10,000

3t² = 10,000

t² = 10,000/3

t = 100/√3

≈ 57.735

d^2C/dt^2 =

C''(t) = [80√(t² + 10,000) - 80t × t/√(t²+10,000)] /√(t²+10,000)

C''(t) = [(80(t²+10,000) - 80t²) / √(t²+10,000)] /√(t²+10,000)

C''(t) = 800,000 / (t² + 10,000)^(3/2)

C''(t) > 0 for all t

Therefore C(t) is minimized at t = 100/√3

C(100/√3) = 80√(10,000/3 + 10,000) + 40 × (1200 - 100/√3)

= 80 √(40,000/3) + 48,000 - 4000/√3

= 16000/√3 + 48,000 - 4000/√3

= 48,000 + 12,000/√3

= 48,000 + 4,000√3

= 4000 (12 + √3)

≈ 54,928.20

Minimum cost is $54,928.20

This occurs when cable is laid underwater from point P to point T(57.735 m east and 100m north of P) and then underground from point T to point Q (1200 - 57.735)

= 1142.265 m

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3 years ago

The number of employees for a certain company has been decreasing each year by 7%. If the company currently has 790 employees a

Vikki [24]

Answer:

The number of employees in 8 years is 442

Step-by-step explanation:

Given:

Decreasing rate = 7%

Current number of employees = 790

To Find:

The number of employees after 8 years is this same rate continues =?

Solution:

Let the number of employees after 8 years be x

The current number of employees is:

$790(1-0.07)^0=790$ ---------------------------------(1)

since the decrase rate is 7% we use 0.07

So after 8 years , eq (1) can be rewritten as

$790(1-0.07)^8= x$

$790(0.93)^8= x$

$790 \times 0.5595= x$

x= 442.005

x= 442 (approx)

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2 years ago

Find the equivalent expression 9 ( 2a + 1

aivan3 [116]

Answer:

Equivalent expression of $9(2a+1)$ is, $18a+9$

Step-by-step explanation:

The distributive property says that:

$a \cdot (b+c) = a\cdot b + a\cdot c$

Given the expression: $9(2a+1)$

Apply the distributive property:

$9 \cdot (2a) +9 \cdot 1$

Simplify:

$18a+9$

Therefore, the equivalent expression of $9(2a+1)$ is, $18a+9$

8 0

3 years ago

Read 2 more answers