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Arada [10]
2 years ago
5

Is the relation given by the set of ordered pairs below a function? (Yes or No)

Mathematics
1 answer:
Arada [10]2 years ago
8 0
Yes it is a function Bc the x values each have a unique y value.
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Th term of a seq uence is n(n-4) /n+3 Work out the sum of the 1st and 6th terms.
AlekseyPX

Answer:

7/12

Step-by-step explanation:

The nth term Tₙ = n(n-4) /n+3.

The 1st term T₁ = 1(1 - 4)/(1 + 3) = -3/4

The 6th term T₆ = 6(6 - 4)/(6 + 3) = 6(2)/9 = 2(2)/3 = 4/3

So,  the sum of the 1st and 6th terms is T₁ + T₆ = -3/4 + 4/3

= (-9 + 16)/12

= 7/12

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
A BOWL HAS SLIPS OF PAPER WITH A SINGLE NUMBER ON IT WITH NUMBERS FROM 2 TO 13. NO NUMBER IS REPEATED. WHAT ARE THE ODDS AGAINST
iren2701 [21]

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3 0
3 years ago
Read 2 more answers
3 ½ x 2/5 *
ki77a [65]

Answer:

Step-by-step explanation:

3\frac{1}{2}=\frac{(3*2)+1}{2}=\frac{7}{2}\\\\\\3\frac{1}{2}*\frac{2}{5}=\frac{7}{2}*\frac{2}{5}=\frac{14}{10}

4 0
2 years ago
What is f(g(x)) when f(x) = x2 + 5, and g(x) = 10 - 5x?
Mashutka [201]

Answer:

D

Step-by-step explanation:

To obtain f(g(x)) substitute x = g(x) into f(x), that is

f(10 - 5x)

= (10 - 5x)² + 5 ← expand (10 - 5x)²

= 100 - 50x - 50x + 25x² + 5 ← collect like terms

= 25x² - 100x + 105 → D

5 0
3 years ago
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