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amm1812
3 years ago
8

3/5 times 2 i need help

Mathematics
2 answers:
solong [7]3 years ago
4 0

Answer:

1.2 <em>[Decimal Form]</em>

\frac{6}{5} <em>[Exact Form]</em>

1\frac{1}{5} <em>[Mixed Number Form]</em>

julia-pushkina [17]3 years ago
3 0

Answer:

6/5

Step-by-step explanation:

\frac{3}{5} * 2 = \frac{6}{5}

please give me brainliest

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Hey can someone please help, i dont know how to do this
yKpoI14uk [10]
Use the tenth’s theory and herons theory u will get it
6 0
3 years ago
Please help
nalin [4]

Answer:

12870ways

Step-by-step explanation:

Combination has to do with selection

Total members in a tennis club = 15

number of men = 8

number of women = 7

Number of team consisting of women will be expressed as 15C7

15C7 = 15!/(15-7)!7!

15C7 = 15!/8!7!

15C7 = 15*14*13*12*11*10*9*8!/8!7!

15C7 = 15*14*13*12*11*10*9/7 * 6 * 5 * 4 * 3 * 2

15C7  = 15*14*13*12*11/56

15C7 = 6,435 ways

Number of team consisting of men will be expressed as 15C8

15C8 = 15!/8!7!

15C8 = 15*14*13*12*11*10*9*8!/8!7!

15C8 = 15*14*13*12*11*10*9/7 * 6 * 5 * 4 * 3 * 2

15C8 = 6,435 ways

Adding both

Total ways = 6,435 ways + 6,435 ways

Total ways = 12870ways

Hence the required number of ways is 12870ways

4 0
3 years ago
A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit
m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0
3 years ago
If you need only 1 c of milk, what is your best choice at the grocery store- a quart container, a pint container, or a 1/2 gallo
kiruha [24]
I don't know the second on but the first is pint
8 0
3 years ago
Lucas made a recipe that needed five-
ser-zykov [4K]

Answer:

2/3 cup

Step-by-step explanation:

Well we see that they both have a common demonitator...6

Next we see the difference on the top of 5-1

After this we add 4 back mon top of the bottom(6)

It can be simplified from 4/6--> 2/3

7 0
3 years ago
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