Based on the graph how many distinct real numbers solutions does the equation X^3 + 6x^2 + 12x + 8 = 0 have?
1 answer:
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For this case we must simplify the following expression:
Simplifying the numerator, dividing all the terms by 4, we have:
We factor by looking for two numbers that when added together give -8 and when multiplied by 12. These are: -6 and -2
So, we have to:
Simplifying the denominator:
We rewrite -17x as -18x + x:
We factor the highest common denominator of each group:
We factor the polynomial by factoring the highest common denominator (x-6):
So, we have to:
Substituting in the original expression we have:
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