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Savatey [412]
3 years ago
13

HELP WILL GIVE BRAINLY NO LINKS PLS​

Mathematics
1 answer:
Andrei [34K]3 years ago
5 0

Answer:

♨ \underline{ \underline{ \large{ \tt{G \: I \: V \: E \: N}}}}:

  • ∠ FED = 115° , ∠ CEB = 160° , ∠ AEF = x°

✧ \underline{ \underline{ \large{ \tt{T\: O \: F \: I \: N \: D}}} }:

  • Value of x

✎ \underline{ \underline{ \large{ \tt{ \: S \: O \: L \: U \: T\: I\: O\: N}}} }:

☃ \large{ \tt{\angle \: CEG =  \angle \: \: FED\: }} [ Being vertically opposite angle ]

↣ \large{ \tt{ \angle \: CEG = 115 \degree}}

☼ \large{ \tt{ \angle \: GEB =  \angle \: CEB -   \angle \: ceg}}

⇢ \large{ \tt{  \angle \: GEB = 160 \degree - 115 \degree = \underline{ 45 \degree}}}

☥ \large{ \tt{ \angle \: AEC=  \angle \: GEB}} [ Being vertically opposite angles ]

⇾ \huge{ \boxed{ \underline{ \large{ \tt{x = 45 \degree}}}}}

♕ Hope I helped ! ♡

☄Have a wonderful day / night ! ☃

❀\underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}✑

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

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I forgot how to do this.... can somebody help?
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\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}



\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template in mind, let's see

3 units to the right, that means C/B = -3 so hmm C = -3 and B = 1 will do, -3/1 = -3

vertical stretch by 2, so A = 2
reflected over the x-axis, so that means is flipped upside-down, so A = -2 then

and shifted down by 3, do D  = -3

\bf f(x)={{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}\implies f(x)={{  -2}}(\mathbb{R})^{{{  1}}x-{{  3}}}-{{3}}\\\\\\ f(x)={{  -2}}(3)^{{{  }}x-{{  3}}}-{{3}}
3 0
4 years ago
Lila sells wedges of cheese at the local farmers' market. To make the wedges, she cuts a big 5-pound block of cheese into 16 pie
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Answer:

Hence the each cheese piece weight equal to 0.3125 pounds

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Now each cheese weigh as follows:

<em>16 cheese pieces of ideal size are considered here so</em>

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i.e Each cheese piece is about 6.25 % of total weight  i.e (6.25*16=100 %)

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