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3 years ago

HELP WILL GIVE BRAINLY NO LINKS PLS

Mathematics

1 answer:

Andrei [34K]3 years ago

5 0

Answer:

♨ $\underline{ \underline{ \large{ \tt{G \: I \: V \: E \: N}}}}:$

∠ FED = 115° , ∠ CEB = 160° , ∠ AEF = x°

✧ $\underline{ \underline{ \large{ \tt{T\: O \: F \: I \: N \: D}}} }:$

Value of x

✎ $\underline{ \underline{ \large{ \tt{ \: S \: O \: L \: U \: T\: I\: O\: N}}} }:$

☃ $\large{ \tt{\angle \: CEG = \angle \: \: FED\: }}$ [ Being vertically opposite angle ]

↣ $\large{ \tt{ \angle \: CEG = 115 \degree}}$

☼ $\large{ \tt{ \angle \: GEB = \angle \: CEB - \angle \: ceg}}$

⇢ $\large{ \tt{ \angle \: GEB = 160 \degree - 115 \degree = \underline{ 45 \degree}}}$

☥ $\large{ \tt{ \angle \: AEC= \angle \: GEB}}$ [ Being vertically opposite angles ]

⇾ $\huge{ \boxed{ \underline{ \large{ \tt{x = 45 \degree}}}}}$

♕ Hope I helped ! ♡

☄Have a wonderful day / night ! ☃

❀ $\underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}$ ✑

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AleksAgata [21]

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3 years ago

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slamgirl [31]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
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f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
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f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
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$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
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\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
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now, with that template in mind, let's see

3 units to the right, that means C/B = -3 so hmm C = -3 and B = 1 will do, -3/1 = -3

vertical stretch by 2, so A = 2
reflected over the x-axis, so that means is flipped upside-down, so A = -2 then

and shifted down by 3, do D = -3

$\bf f(x)={{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}\implies f(x)={{ -2}}(\mathbb{R})^{{{ 1}}x-{{ 3}}}-{{3}}\\\\\\ f(x)={{ -2}}(3)^{{{ }}x-{{ 3}}}-{{3}}$

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4 years ago

Lila sells wedges of cheese at the local farmers' market. To make the wedges, she cuts a big 5-pound block of cheese into 16 pie

Anestetic [448]

Answer:

Hence the each cheese piece weight equal to 0.3125 pounds

Step-by-step explanation:

Given;

5 pound of cheese block cut down into 16 pieces

To Find:

How much does each wedge of each cheese weigh

Solution:

Now each cheese weigh as follows:

<em>16 cheese pieces of ideal size are considered here so</em>

<em>16 piece equally contribute the the total weight of 5 pounds.</em>

So 5 pound in divided into 16 pieces

i.e 5/16=0.3125 pound per pieces

Hence the each cheese piece weight equal to 0.3125 pounds

i.e Each cheese piece is about 6.25 % of total weight i.e (6.25*16=100 %)

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3 years ago

HELP WILL GIVE BRAINLY NO LINKS PLS​

HELP WILL GIVE BRAINLY NO LINKS PLS