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Stells [14]
2 years ago
11

Which expresion is equivalent to the given expresion (3m-4)³(3m³)

Mathematics
1 answer:
ivolga24 [154]2 years ago
7 0

The equivalent expression of (3m^{-4})^3 * (3m^3) is 729m^{-9}

<h3>How to determine the equivalent expression?</h3>

The expression is given as:

(3m^{-4})^3 * (3m^3)

Expand the brackets

27m^{-12} * 27m^3

Apply the law of indices

729m^{-12+3}

Evaluate the sum

729m^{-9}

Hence, the equivalent expression of (3m^{-4})^3 * (3m^3) is 729m^{-9}

Read more about equivalent expression at:

brainly.com/question/2972832

#SPJ1

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25 Points Please help
zysi [14]

Answer:

It's Not possible that both answers are correct because one person is adding and the other person is using subtraction meaning one person would have a higher number for there answer and the other person would have a lesser number for their answer. In some cases it's not possible but in other cases it is possible

Step-by-step explanation:

Can i have branliest?

6 0
3 years ago
Read 2 more answers
Let $$X_1, X_2, ...X_n$$ be uniformly distributed on the interval 0 to a. Recall that the maximum likelihood estimator of a is $
Solnce55 [7]

Answer:

a) \hat a = max(X_i)  

For this case the value for \hat a is always smaller than the value of a, assuming X_i \sim Unif[0,a] So then for this case it cannot be unbiased because an unbiased estimator satisfy this property:

E(a) - a= 0 and that's not our case.

b) E(\hat a) - a= \frac{na}{n+1} - a = \frac{na -an -a}{n+1}= \frac{-a}{n+1}

Since is a negative value we can conclude that underestimate the real value a.

\lim_{ n \to\infty} -\frac{1}{n+1}= 0

c) P(Y \leq y) = P(max(X_i) \leq y) = P(X_1 \leq y, X_2 \leq y, ..., X_n\leq y)

And assuming independence we have this:

P(Y \leq y) = P(X_1 \leq y) P(X_2 \leq y) .... P(X_n \leq y) = [P(X_1 \leq y)]^n = (\frac{y}{a})^n

f_Y (Y) = n (\frac{y}{a})^{n-1} * \frac{1}{a}= \frac{n}{a^n} y^{n-1} , y \in [0,a]

e) On this case we see that the estimator \hat a_1 is better than \hat a_2 and the reason why is because:

V(\hat a_1) > V(\hat a_2)

\frac{a^2}{3n}> \frac{a^2}{n(n+2)}

n(n+2) = n^2 + 2n > n +2n = 3n and that's satisfied for n>1.

Step-by-step explanation:

Part a

For this case we are assuming X_1, X_2 , ..., X_n \sim U(0,a)

And we are are ssuming the following estimator:

\hat a = max(X_i)  

For this case the value for \hat a is always smaller than the value of a, assuming X_i \sim Unif[0,a] So then for this case it cannot be unbiased because an unbiased estimator satisfy this property:

E(a) - a= 0 and that's not our case.

Part b

For this case we assume that the estimator is given by:

E(\hat a) = \frac{na}{n+1}

And using the definition of bias we have this:

E(\hat a) - a= \frac{na}{n+1} - a = \frac{na -an -a}{n+1}= \frac{-a}{n+1}

Since is a negative value we can conclude that underestimate the real value a.

And when we take the limit when n tend to infinity we got that the bias tend to 0.

\lim_{ n \to\infty} -\frac{1}{n+1}= 0

Part c

For this case we the followng random variable Y = max (X_i) and we can find the cumulative distribution function like this:

P(Y \leq y) = P(max(X_i) \leq y) = P(X_1 \leq y, X_2 \leq y, ..., X_n\leq y)

And assuming independence we have this:

P(Y \leq y) = P(X_1 \leq y) P(X_2 \leq y) .... P(X_n \leq y) = [P(X_1 \leq y)]^n = (\frac{y}{a})^n

Since all the random variables have the same distribution.  

Now we can find the density function derivating the distribution function like this:

f_Y (Y) = n (\frac{y}{a})^{n-1} * \frac{1}{a}= \frac{n}{a^n} y^{n-1} , y \in [0,a]

Now we can find the expected value for the random variable Y and we got this:

E(Y) = \int_{0}^a \frac{n}{a^n} y^n dy = \frac{n}{a^n} \frac{a^{n+1}}{n+1}= \frac{an}{n+1}

And the bias is given by:

E(Y)-a=\frac{an}{n+1} -a=\frac{an-an-a}{n+1}= -\frac{a}{n+1}

And again since the bias is not 0 we have a biased estimator.

Part e

For this case we have two estimators with the following variances:

V(\hat a_1) = \frac{a^2}{3n}

V(\hat a_2) = \frac{a^2}{n(n+2)}

On this case we see that the estimator \hat a_1 is better than \hat a_2 and the reason why is because:

V(\hat a_1) > V(\hat a_2)

\frac{a^2}{3n}> \frac{a^2}{n(n+2)}

n(n+2) = n^2 + 2n > n +2n = 3n and that's satisfied for n>1.

8 0
4 years ago
Fill in the blanks in each rule.
Romashka [77]

The ratio of their surface areas will be a²/b². And the ratio of their volumes a³/b³.

<h3>What are the surface area and the volume of an object?</h3>

The size is the amount of space covered by a two-dimensional hard surface.

The volume of an element or compound is the sufficient space it takes up, calculated in cubic units.

1.  The ratio of the surface area of similar solids

If the ratio of the corresponding edge lengths of two similar solids is a:b, then the ratio of their surface areas will be a²/b².

2.  The ratio of the volume of similar solids

If the ratio of the corresponding edge lengths of two similar solids is a:b, then the ratio of their volumes a³/b³.

More about the surface area and the volume link is given below.

brainly.com/question/15585435

#SPJ1

3 0
2 years ago
Will mark brainliest!!! Two trains leave towns 663 kilometers apart at the same time and travel toward each other. One train tra
topjm [15]

Answer: rate of train A = 120 km/h

rate of train B = 101 km/h

Step-by-step explanation:

Let x = the speed of train A

Let y = the speed of train B

One train travels 19 km/h slower than the other. Let train B be the slower train. Therefore,

x = y + 19 - - - - - - - - - -1

Recall

Speed = distance/time

Distance = speed × time

If they meet in 3 hours, it means that train A has travelled a distance of

x × 3 = 3x km

And train B has travelled a distance of y × 3 = 3y km

Train A and Train B were 663 kilometers apart when they left their respective destinations. They left at the same time and travelled towards each other. This means that if they meet in 3hours time, they must have covered a total of 663 km. Therefore,

3x + 3y = 663 - - - - - - - - - 2

Substituting x = y + 19 into equation 2, it becomes

3(y + 19) + 3y = 663

3y + 57 + 3y = 663

6y + 57 = 663

6y = 663 - 57 = 606

y = 606/6 = 101 km/h

x = y + 19 = 101 + 19

x = 120 km/h

5 0
4 years ago
Evaluate the expression for y = 2. Simplify your answer.<br><br> 4/y=
yanalaym [24]
=2 all u have to do is divide 4 by 2
3 0
3 years ago
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