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Arlecino [84]
2 years ago
5

What are the coordinates of the fourth vertex of parallelogram ABCD? D( , )

Mathematics
1 answer:
inessss [21]2 years ago
7 0
 The answer has to be D(3,0)
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Marie has a small copy of Rene Magritte's famous painting, The Schoolmaster. Her copy has dimensions 2 inches by 1.5 inches. The
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A. Find the dimensions of the original painting.

 

Since the scale is 1 in : 40 cm

2 in ( 40 cm / 1 in) = 80 cm

1.5 in ( 40 cm / 1 in) = 60 cm

80 cm by 60 cm

 

B. Find the area of the original painting.

<span>A =  80 cm x 60 cm = 4800 sq cm</span>

 

C. Since 1 inch is 2.54 cm, find the dimensions of the original painting in inches.

80 cm ( 1 in / 2.54 cm) = 31.5 in

60 cm ( 1 in / 2.54 cm) = 23.6 in

 

D, Find the area of the original painting in square inches.

A = 31.5 in x 23.6 in = 743.4 sq in

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3 years ago
1 Simplify the following expressions: 1) -4(a + 2) - a
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1.C) -4a-8-a = -5a-8
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8 0
2 years ago
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Can someone please answer this question please help please answer it correctly and please show work please help I need it please
mr_godi [17]

Answer:

Step-by-step explanation:

24)

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.5(pi)= about 1.6

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equation-     T= 12.17+0.75v

105.75= 12.17 + .75v

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93.58= .75v

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Suppose there are two circles where the radius of one circle is twice the radius of the other circle. Each circle has an arc whe
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Answer:

L=2l where l,L denote arc lengths of two circles

Step-by-step explanation:

Let l,L denote arc lengths of two circles, r,R denote corresponding radii and

\alpha _1\,,\alpha _2 denote the corresponding central angles.

So,

l=r\alpha _1 and L=R\alpha _2

This implies \alpha _1=\frac{l}{r} and \alpha _2=\frac{L}{R}

As each circle has an arc where the measures of the corresponding central angles are the same, \alpha _1=\alpha _2

\frac{l}{r}=\frac{L}{R}

As radius of one circle is twice the radius of the other circle,

R=2r

\frac{l}{r}=\frac{L}{2r}\\\frac{l}{1} =\frac{L}{2}\\L=2l

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2 years ago
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