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Alona [7]
2 years ago
8

Solve For x

e=" \large \frak{5x + 15 = 30}" alt=" \large \frak{5x + 15 = 30}" align="absmiddle" class="latex-formula">

Tysm!:)​
Mathematics
2 answers:
True [87]2 years ago
7 0
Ans : x = 3

5x + 15 = 30
minus 15 on both sides, 5x = 15
then divide both sides by 5 so, x = 3
yKpoI14uk [10]2 years ago
6 0

\boldsymbol{5x+15=30}

Subtract 15 from both sides.

  • \boldsymbol{5x=30-15 }

Subtract 15 from 30 to get 15.

  • \boldsymbol{5x=15 }

Divide both sides by 5.

  • \boldsymbol{x=\dfrac{15}{5} }

Divide 15 by 5 to get 3.

  • \boldsymbol{x=3 \ \ \to \ \ \ Answer}

<h3>Verification</h3>

Let x=3.

  • \bf{5\times3+15=30 \ \ \to \ \ \ Multiply }
  • \bf{15+15=30 \ \ \to \ \ \ Add}
  • \bf{30=30 \to \ The \ equality \ is \ fulfilled.}

Checked ✅

\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}

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How to slove this problem?
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So, since the polygons are similar, they will share a scale factor. 

The dilation is a reduction.

SF= preimage/image

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<span>ʕ •ᴥ•ʔ</span>




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