Add 2 lb 9oz + 1 lb 12 oz

1 answer:

4 0

2 lb 9 oz
+ 1 lb 12 oz

3 lb 21 oz which equals
4 pounds 5 ounces

and here is a good calculator for those non-metric calculations:
http://www.1728.org/nonmtric.htm

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Find (if possible) the complement and the supplement of each angle. (if not possible, enter impossible.) (a) π 10 complement rad

blagie [28]

In this question, we have to find the complement and supplement of the given angles .

Complementary angles are those angles whose sum is 90 degree and supplementary angles are those angles whose sum is 180 degree.

So to find the complement and supplement angles, we need to subtract the given angles from pi/2 and pi respectively .

$\frac{ \pi}{10}
\\
complement \ angle = \frac{ \pi}{2} - \frac{ \pi}{10} \\ = \frac{4 \pi}{10} = \frac{ 2 \pi}{5}
\\
Supplement \ angle = \pi - \frac{ \pi}{10} = \frac{9 \pi}{10}$

$\frac{9 \pi}{10}
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Complement \ angle = \frac{ \pi}{2} - \frac{9 \pi}{10} = \frac{-4 \pi}{10} = -\frac{2 \pi}{5}
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Supplement \ angle = \pi - \frac{9 \pi}{10} = \frac{ \pi}{10}$

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Two years of local Internet service cost $685, including the installation fee of $85. What is the monthly fee?

AnnZ [28]

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Triangle FGH has the following side lengths: FG = 5 ft, GH = 10 ft, HF = 12 ft Triangle PQR is similar to triangle FGH. The long

7nadin3 [17]

The first thing we must do for this case is find the scale factor.
We have then that for the larger side of both triangle, the scale factor is:
$k = \frac{RP}{HF}$
$k = \frac{7.2}{12}$
$k = 0.6$
To find the other two sides, we must apply the scale factor on each side of the triangle FGH.
We have then:

For PQ
$PQ = k * FG

PQ = 0.6 * 5

PQ = 3$

For QR
$QR = k * GH

QR = 0.6 * 10

QR = 6$

Answer:
You have that the lengths for the other two sides of triangle PQR are:
$PQ = 3

QR = 6$

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blondinia [14]

I would say the answer is c

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Vikentia [17]

The answer is 8 sugar cubes

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